3 years ago

How far away are the Stars?

Physics

1 answer:

Shtirlitz [24]3 years ago

8 0

Answer:

25,300,000,000,000 miles away

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A snail slowly travels down the sidewalk at a pace of 4 cm/s. how long will it take the snail to reach a distance of 20 cm?

egoroff_w [7]

It’s gonna take it 5 cm to reach the distance

8 0

3 years ago

Calculate the total resistance in a parallel circuit made up of resistances of 2Ω, 3Ω, and 4Ω. (Hint: When converting to a decim

natta225 [31]

Answer:

Total resistance = 0.92Ω

Explanation:

For parallel connected resistors we have effective resistance

$\frac{1}{R_{eff}}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}+.....$

Here parallel circuit made up of resistances of 2Ω, 3Ω, and 4Ω.

That is

R₁ = 2Ω

R₂ = 3Ω

R₃ = 4Ω

Substituting

$\frac{1}{R_{eff}}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}\\\\\frac{1}{R_{eff}}=\frac{1}{2}+\frac{1}{3}+\frac{1}{4}\\\\\frac{1}{R_{eff}}=\frac{6+4+3}{12}\\\\R_{eff}=\frac{12}{13}=0.92ohm$

Total resistance = 0.92Ω

6 0

3 years ago

A 1.0 ball moving at 2.0 / perpendicular to a wall rebounds from the wall at 1.5 /. If the ball was in contact with the wall for

xxTIMURxx [149]

Answer:

Explanation:

We have a simple problem of momentum here.

ΔMomentum= mΔv= FΔt

Solve for F

mΔv/Δt=F

Plug in givens

1*(2-1.5)/0.1=F

F=5N

4 0

3 years ago

Every summer I drive to Pennsylvania. It is 895 km to get there. If I average 100 km/hr, how much time will I spend driving?

Ivan

Answer the time you bee spending driving iss 795 because 895-795=100

Explanation:

6 0

2 years ago

A coil of 40 turns is wrapped around a long solenoid of cross-sectional area 7.5×10−3m2. The solenoid is 0.50 m long and has 500

defon

To solve this problem it is necessary to apply the concepts related to mutual inductance in a solenoid.

This definition is described in the following equation as,

$M = \frac{\mu_0 N_1 N_2A_1}{l_1}$

Where,

$\mu =$ permeability of free space

$N_1 =$ Number of turns in solenoid 1

$N_2 =$ Number of turns in solenoid 2

$A_1=$ Cross sectional area of solenoid

l = Length of the solenoid

Part A )

Our values are given as,

$\mu_0 = 4\pi *10^{-7}H/m$

$N_1 = 500$

$N_2 = 40$

$A = 7.5*10^{-4}m^2$

$l = 0.5m$

Substituting,

$M = \frac{\mu_0 N_1 N_2A_2}{l_1}$

$M = \frac{(4\pi *10^{-7})(500)(40)(7.5*10^{-4})}{0.5}$

$M = 3.77*10^{-4}H$

PART B) Considering that many of the variables remain unchanged in the second solenoid, such as the increase in the radius or magnetic field, we can conclude that mutual inducantia will appear the same.

8 0

3 years ago