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Volgvan
3 years ago
12

5.) A 2000 N bear slides down a tree at a constant velocity, what is the

Physics
1 answer:
PilotLPTM [1.2K]3 years ago
4 0

Answer:

2000 N

1600 N

Explanation:

Step 1:

It is given that the bear's weight is 2000 N and it slides down the tree with constant velocity. Since it is sliding with constant velocity the overall force  on the bear is zero. The weight of the bear acting downward balances the upward force caused due to friction. Hence the upward force equals the weight 2000 N.  

Step 2:

It is given that the bear slides down with an acceleration 2 m/sec sq  

Weight of the bear = 2000 N

Mass of the bear = 2000/10 (taking g = 10 m/sec sq)=200 kg

Force = Mass * Acceleration

Hence net force acting downward = 200*2=400 N.

Net force = Weight of bear - Force acting upward on the bear

400 = 2000 -  Force acting upward on the bear

Force on the bear acting upward = 2000 - 400 = 1600 N

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The maximum height attained is 460 m.

<h3>What is the maximum height?</h3>

We know that the final velocity of a body is 0 m/s at the maximum height which is the greatest height that is attained by the body. We now use the formula;

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Given that v = 0 m/s

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h = u^2/2g

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u = initial velocity

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g = acceleration due to gravity

h = (95)^2/2 * 9.8

h = 460 m

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6 0
1 year ago
Occasionally, people can survive falling large distances if the surface they land on is soft enough. During a traverse of Eiger'
uranmaximum [27]

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4611.58 ft/s²

Explanation:

t = Time taken

u = Initial velocity

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Equation of motion

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 32.174\times 516+0^2}\\\Rightarrow v=182.218\ ft/s

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8 0
3 years ago
On a graph of position vs. time, a negative slope means what about motion of the object?​
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Answer:

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3 years ago
For an RLC circuit in the limit of very high frequency, what is the effective behavior of the capacitor and the inductor in the
Aliun [14]

Answer:

Explanation:

Given

In R-L-C circuit frequency is very high

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3 0
3 years ago
Julietta and Jackson are playing miniature golf. Julietta's ball rolls into a long. Straight upward incline with a speed of 2.95
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Answer:

The length of the incline is 3.504 meters.

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\Delta s = 3.504\,m

The length of the incline is 3.504 meters.

6 0
2 years ago
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