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3 years ago

11

What is an equation of the line that passes through the points (-6, -5) and (-3,0)? Put your answer in fully reduced form.

1 answer:

MrMuchimi3 years ago

6 0

Answer:

y = 5/3x +5

Step-by-step explanation:

The two-point form of the equation of a line is useful here.

y = (y2 -y1)/(x2 -x1)(x -x1) +y1

y = (0 -(-5))/(-3 -(-6))(x -(-6)) -5

y = 5/3(x +6) -5

y = 5/3x +5 . . . . slope-intercept form

5x -3y = -15 . . . .standard form

_____

There is no "fully reduced" form of the equation of a line. There are slope-intercept form, point-slope form, two-point form, standard form, general form, intercept form, and some others. We assume that "fully reduced" applies to any fractions in the equation. The "slope-intercept" form has a fraction, so perhaps that's the form that is required.

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Step-by-step explanation:

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Suppose line segment AB has one endpoint at A(0, 0). What are the coordinates of B if (5, 3) is 1/3 of the way from A to B?

prisoha [69]

Answer:

$B(x_2,y_2)= (20,12)$

Step-by-step explanation:

Given

$A = (0,0)$

$Ratio; m : n = 1 : 3$

$Point\ at\ 1 : 3 = (5,3)$

Required

Coordinates of B

This question will be answered using line ratio formula;

$(x,y) = (\frac{mx_2 + nx_1}{m + n},\frac{my_2 + ny_1}{m + n})$

In this case:

$(x,y) = (5,3)$

$(x_1,y_1) = (0,0)$

$m : n = 1 : 3$

Solving for $(x_2,y_2)$

$(x,y) = (\frac{mx_2 + nx_1}{m + n},\frac{my_2 + ny_1}{m + n})$ becomes

$(5,3) = (\frac{1 * x_2 + 3 * 0}{1 + 3},\frac{1 * y_2 + 3 * 0}{1 + 3})$

$(5,3) = (\frac{x_2 + 0}{4},\frac{y_2 + 0}{4})$

$(5,3) = (\frac{x_2}{4},\frac{y_2}{4})$

Comparing the right hand side to the left;

$\frac{x_2}{4} = 5$ -- (1)

$\frac{y_2}{4} = 3$ -- (2)

Solving (1)

$x_2 = 5 * 4$

$x_2 = 20$

Solving (2)

$y_2 = 3 * 4$

$y_2 = 12$

Hence;

$B(x_2,y_2)= (20,12)$

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Step-by-step explanation:

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