Y =ax² + bx +c
1) Point (0,7)
7 = a*0² +b*0 +c
c = 7
y=ax² + bx + 7
2) Point (1,4)
4=a*1² + b*1 + 7, ----> 4 = a +b + 7, ------>
a+b= - 3
3) Point (2, 5)
5=a*2² + b*2 + 7, ----> 5=4a+2b +7,---> -2=4a+2b, ---->
-1=2a + b
4)
a+b= - 3, ----> b= -3 - a (substitute in the second equation)
2a+b= -1
2a - 3 - a = -1, ----> a - 3 = -1,
a =2
5) a+b= - 3
2 + b = -3
b = -5
y=2x² - 5x + 7
3(7v-5)-v(10v-9) = 21v - 15 -10v² + 9v = - 10v² + 30v - 15
Answer:
Step-by-step explanation:
R = 9x + 8y
4 = 9x + 8*8
4 = 9x + 64
Subtract 64 from both sides
4 - 64 = 9x + 64 - 64
-60 = 9x
Divide both sides by 9
-60/9 = 9x/9
-20/3 = x
x = -6 2/3
In ∆MKP and ∆MNP
MK = MN
PK = NP
MP = MP
SO ∆MKP AND ∆MNP ARE CONGRUENT.
SO m<PMN = m<PMK
m<NMK = 50
=> m<PMN + m<PMK = 50
=> 2 m<PMK = 50
=> m<PMK = 50/2 = 25°
Answer:
A: y = -2x^2
Step-by-step explanation:
The parent function would be y = x^2 since it is a parabola.
Since the function has a vertical stretch by 2, y = 2x^2.
Finally, the function is inverted so the final equation would be y = -2x^2