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Mamont248 [21]
3 years ago
10

Which ratio forms a proportion with 16:20 A. 4:10 B. 32:50 C. 8:12 D. 4:5

Mathematics
2 answers:
kicyunya [14]3 years ago
6 0
D 4:5 as both number times by 4 to get 16:20
Arte-miy333 [17]3 years ago
4 0
It would be D! 4:5 ((:
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If the parallelogram floor needs a base of 16 feet,what will the height of the floor be
nydimaria [60]

Answer:

See Explanation

Step-by-step explanation:

<em>The question is incomplete because the area of the parallelogram is missing. However, the following will guide you in answering the question</em>

Given

Base = 16\ ft

Required

Determine the Height

Area of a Parallelogram is:

Area = Base * Height

Make Height the subject

Height = \frac{Area}{Base}

Substitute 16 for Base

Height = \frac{Area}{16}

This implies that you divide the value of area by 16 to get the height of the parallelogram.

Take for instance;

Area = 64ft\²

The height would be

Height = \frac{64}{16}

Height = 4\ ft

Or

Area = 80ft\²

The height would be

Height = \frac{80}{16}

Height = 5\ ft

7 0
3 years ago
PLEASE HELP ME, I HAVE NO IDEA!
ivanzaharov [21]

b is 14 for sure

you are welcome to ask me anything



3 0
3 years ago
F) Two numbers are in the ratio 5:4. If they differ by 12, what are the numbers?
Iteru [2.4K]

Answer:

First number = 60 and another number = 48

Step-by-step explanation:

Let two numbers are 5x and 4x.

The two number are differ by 12. We need to find the numbers.

ATQ,

5x-4x = 12

x = 12

Now first number = 5x

= 5(12)

= 60

Other number = 4x

= 4(12)

= 48

Hence, the numbers are 60 and 48.

8 0
3 years ago
9(3+c+4) what is the answer
zzz [600]

Answer:

the answer is 9c+63

Step-by-step explanation:

4 0
3 years ago
Two customers went to a post office to buy postcards and large envelopes. Each postcard
astraxan [27]

The right answer is Option A.

Step-by-step explanation:

Let,

x be the postcards

y be the large envelops

According to given statement;

14x+5y=12   Eqn 1

10x+15y=24.80   Eqn 2

Multiplying Eqn 1 by 3;

3(14x+5y=12)\\42x+15y=36\ \ \ Eqn \ 3

Subtracting Eqn 2 from Eqn 3;

(42x+15y)-(10x+15y)=36-24.80\\42x+15y-10x-15y=11.20\\32x=11.20\\

Dividing both sides by 32

\frac{32x}{32}=\frac{11.20}{32}\\x=0.35

Putting x=0.35 in Eqn 1;

14(0.35)+5y=12\\4.90+5y=12\\5y=12-4.90\\5y=7.10

Dividing both sides by 5

\frac{5y}{5}=\frac{7.10}{5}\\y=1.42

Therefore, one large envelope costs $1.42

The right answer is Option A.

Keywords: linear equations, subtraction

Learn more about linear equations at:

  • brainly.com/question/9738996
  • brainly.com/question/10015690

#LearnwithBrainly

4 0
3 years ago
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