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3 years ago

Is y=x squared +2 a linear function

2 answers:

7 0

No, this would not be a linear function. Being linear means it creates a straight line, but this function has an x squared. Anytime x^2 is in a function, the graph is a u shape, called a parabola. A simple linear function is y=x :D

MaRussiya [10]3 years ago

3 0

Y=x^2 + 2 is not a linear function. This is because the x has power. If it was only x then it would be linear function. So x^2 +2 is quadratic function. However if it was x^3, it would be quadratic; it would be cubic. Therefore fore only x squared is quadratic.

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If 8y-8=24, find the value of 2y

algol [13]

8 is the answer
for 2y

6 0

3 years ago

Read 2 more answers

What is the slope of this line? -2x + 3y =-6

valkas [14]

Answer:

Slope: 2/3

Step-by-step explanation:

You have to first write the equation into slope-intercept form...

y = mx + b

So...

-2x + 3y = -6

becomes...

3y = 2x - 6

y = 2/3x - 2

Which means...

2/3 is the slope

Hope this help :)

Let me know if there are any mistakes!!

4 0

2 years ago

If x and y vary inversely and x = 5 when y = -3.5, what is the value of x when y = 10?

Solnce55 [7]

Answer:

Step-by-step explanation:

k = xy

Putting values of x and y in the equation

k = (5)(-3.5)

= - 17.5

Finding value of x when y = 10

k = xy

- 17.5 = x10

Bringing like terms on one side

- 17.5 - 10 = x

-27.5 = x

5 0

3 years ago

Select the action you would use to solve 3x = 12. Then select the property

podryga [215]

Answer:

C: Divide both sides by 3

F: Division property of equality

Step-by-step explanation:

$3x=12\\x=\frac{12}{3}\\x=4$

3 0

2 years ago

Quantitative noninvasive techniques are needed for routinely assessing symptoms of peripheral neuropathies, such as carpal tunne

Pavlova-9 [17]

Answer:

$t=\frac{2.35-1.83}{\sqrt{\frac{0.88^2}{10}+\frac{0.54^2}{7}}}}=1.507$

$p_v =P(t_{(15)}>1.507)=0.076$

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and the group CTS, NOT have a significant higher mean compared to the Normal group at 1% of significance.

Step-by-step explanation:

1) Data given and notation

$\bar X_{CTS}=2.35$ represent the mean for the sample CTS

$\bar X_{N}=1.83$ represent the mean for the sample Normal

$s_{CTS}=0.88$ represent the sample standard deviation for the sample of CTS

$s_{N}=0.54$ represent the sample standard deviation for the sample of Normal

$n_{CTS}=10$ sample size selected for the CTS

$n_{N}=7$ sample size selected for the Normal

$\alpha=0.01$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean for the group CTS is higher than the mean for the Normal, the system of hypothesis would be:

Null hypothesis: $\mu_{CTS} \leq \mu_{N}$

Alternative hypothesis: $\mu_{CTS} > \mu_{N}$

If we analyze the size for the samples both are less than 30 so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{CTS}-\bar X_{N}}{\sqrt{\frac{s^2_{CTS}}{n_{CTS}}+\frac{s^2_{N}}{n_{N}}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{2.35-1.83}{\sqrt{\frac{0.88^2}{10}+\frac{0.54^2}{7}}}}=1.507$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n_{CTS}+n_{N}-2=10+7-2=15$

Since is a one side right tailed test the p value would be:

$p_v =P(t_{(15)}>1.507)=0.076$

We can use the following excel code to calculate the p value in Excel:"=1-T.DIST(1.507,15,TRUE)"

Conclusion

6 0

3 years ago