Step-by-step explanation:
We need to find the value of the function at the indicated value.
![f(x)= 6x^2+ 5x -12](https://tex.z-dn.net/?f=f%28x%29%3D%206x%5E2%2B%205x%20-12)
Indicated values are : f(-7), f(0), f(6), f(7)
To find f(-7), put x = -7 in the given function
![f(-7)= 6(-7)^2+ 5(-7) -12=247](https://tex.z-dn.net/?f=f%28-7%29%3D%206%28-7%29%5E2%2B%205%28-7%29%20-12%3D247)
To find f(0), put x = 0 in the given function
![f(0)= 6(0)^2+ 5(0) -12=-12](https://tex.z-dn.net/?f=f%280%29%3D%206%280%29%5E2%2B%205%280%29%20-12%3D-12)
To find f(6), put x = 6 in the given function
![f(6)= 6(6)^2+ 5(6) -12=234](https://tex.z-dn.net/?f=f%286%29%3D%206%286%29%5E2%2B%205%286%29%20-12%3D234)
To find f(7), put x = 7 in the given function
![f(7)= 6(7)^2+ 5(7) -12=317](https://tex.z-dn.net/?f=f%287%29%3D%206%287%29%5E2%2B%205%287%29%20-12%3D317)
Hence, this is the required solution.