.35x=40
/.35 /.35
X= 40/.35
X = 114.2857
Given that <span>Line WX is congruent to Line XY and Line XZ bisects Angle WXY.
We prove that triangle WXZ is congruent to triangle YXZ as follows:
![\begin{tabular} {|c|c|} Statement&Reason\\[1ex] \overline{WX}\cong\overline{XY},\ \overline{XZ}\ bisects\ \angle WXY&Given\\ \angle WXY\cong\angle YXZ & Deifinition of an angle bisector\\ \overline{XZ}\cong\overline{ZX}&Refrexive Property of \cong\\ \triangle WXZ\cong\triangle YXZ&SAS \end{tabular}](https://tex.z-dn.net/?f=%5Cbegin%7Btabular%7D%0A%7B%7Cc%7Cc%7C%7D%0AStatement%26Reason%5C%5C%5B1ex%5D%0A%5Coverline%7BWX%7D%5Ccong%5Coverline%7BXY%7D%2C%5C%20%5Coverline%7BXZ%7D%5C%20bisects%5C%20%5Cangle%20WXY%26Given%5C%5C%0A%5Cangle%20WXY%5Ccong%5Cangle%20YXZ%20%26%20Deifinition%20of%20an%20angle%20bisector%5C%5C%0A%5Coverline%7BXZ%7D%5Ccong%5Coverline%7BZX%7D%26Refrexive%20Property%20of%20%5Ccong%5C%5C%0A%5Ctriangle%20WXZ%5Ccong%5Ctriangle%20YXZ%26SAS%0A%5Cend%7Btabular%7D)
</span>
So we know the slope has to be -3 and the y intercept is 2. y intercept looks like (0,2). since we know this we automatically can rule out B since it has (0,0).
let’s find the slope of A
-9- -5
-3- - 1
the slope= -4/-2= 2
we know it’s not A because the slope is not -3
let’s find the slope of C
-17- -8
-5- -2
slope= -9/-3=3
we know it’s not C because the slope is not -3. we could directly assume that D is the answer no but we’ll still find the slope just to be sure
let’s find the slope of D
14-8
-4- -2
slope=6/-2= -3
the answer is D!!
Answer:
did not understand ur q.a
I ain't gonna explain how I got to this cuz I'm quite tired rn but trust me the answer is 2c²
