9+4+7+3+10+9=42
42÷6= 34.5. I believe "mean" is the same as avgerage.
Hello there!
For this you simply need to give both fractions a common denominator!
The easiest way to do this specific problem would be to make the denominator 12. Why 12? Because 4 x 3 = 12.
So:
1/4 --> ?/12 --> 1 (3) / 12 --> 3/12
2/3 --> ?/12 --> 2 (4) / 12 --> 8/12
Total amount of time means the sum (adding them together).
When adding fractions, you MUST have a common denominator! (Which is what we just did).
So 3/12 + 8/12 = (8+3) / 12 = 11/12 hours
Notice how the denominator stayed the same? When adding/subtracting fractions, the denominator stays the same! :)
Hope this helped!
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1/2 times 6 = 1/2 * 6
so in order to make this multiplication you have to turn 6 to a fraction, 6 is equal to 6/1
so , the way to multiply them is multiply the top with the top and it will be the top in the answer and the exact same with the bottoms
6*1= 6
2*1=2
so the fraction is 6/2, since a fraction is basicly a division
6/2 = 3
so the answer to your question is 3
i hope i helped you
Answer:
320+40=360
Step-by-step explanation:
8(40+5)
320+40=360
Answer:
c) Is not a property (hence (d) is not either)
Step-by-step explanation:
Remember that the chi square distribution with k degrees of freedom has this formula
Where N₁ , N₂m .... are independent random variables with standard normal distribution. Since it is a sum of squares, then the chi square distribution cant take negative values, thus (c) is not true as property. Therefore, (d) cant be true either.
Since the chi square is a sum of squares of a symmetrical random variable, it is skewed to the right (values with big absolute value, either positive or negative, will represent a big weight for the graph that is not compensated with values near 0). This shows that (a) is true
The more degrees of freedom the chi square has, the less skewed to the right it is, up to the point of being almost symmetrical for high values of k. In fact, the Central Limit Theorem states that a chi sqare with n degrees of freedom, with n big, will have a distribution approximate to a Normal distribution, therefore, it is not very skewed for high values of n. As a conclusion, the shape of the distribution changes when the degrees of freedom increase, because the distribution is more symmetrical the higher the degrees of freedom are. Thus, (b) is true.