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2 years ago

Find the product 0.025 x 7 A. 0.0175 B: 0.175 C. 1.75 D. 17.5

Mathematics

2 answers:

sattari [20]2 years ago

8 0

Answer:

Step-by-step explanation:

used a calucator

Nookie1986 [14]2 years ago

6 0

A. 0.0175 you have a calculator but thanks for the answer?? I asked siri

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Can you help me solve this problem

Fiesta28 [93]

112 <span>≥ b+128

First: You would subtract 128 on both sides of your sign
You would get: -16</span><span>≥ b <That is your answer

HOPE THIS HELPS! ^_^</span>

7 0

3 years ago

Read 2 more answers

Can someone please help

allsm [11]

Answer:

Concurrent as my perception

3 0

3 years ago

To estimate the mean height μ of male students on your campus,you will measure an SRS of students. You know from government data

nexus9112 [7]

Answer:

a) $\sigma = 0.167$

b) We need a sample of at least 282 young men.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

This Zscore is how many standard deviations the value of the measure X is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

(a) What standard deviation must x have so that 99.7% of allsamples give an x within one-half inch of μ?

To solve this problem, we use the 68-95-99.7 rule. This rule states that:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviations of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we want 99.7% of all samples give X within one-half inch of $\mu$ . So $X - \mu = 0.5$ must have $Z = 3$ and $X - \mu = -0.5$ must have $Z = -3$ .

$Z = \frac{X - \mu}{\sigma}$

$3 = \frac{0.5}{\sigma}$

$3\sigma = 0.5$

$\sigma = \frac{0.5}{3}$

$\sigma = 0.167$

(b) How large an SRS do you need to reduce the standard deviationof x to the value you found in part (a)?

You know from government data that heights of young men are approximately Normal with standard deviation about 2.8 inches. This means that $\sigma = 2.8$

The standard deviation of a sample of n young man is given by the following formula

$s = \frac{\sigma}{\sqrt{n}}$

We want to have $s = 0.167$

$0.167 = \frac{2.8}{\sqrt{n}}$

$0.167\sqrt{n} = 2.8$

$\sqrt{n} = \frac{2.8}{0.167}$

$\sqrt{n} = 16.77$

$\sqrt{n}^{2} = 16.77^{2}$

$n = 281.23$

We need a sample of at least 282 young men.

6 0

3 years ago

6. The mass of one coin is 16.718 grams. The mass of a second coin is 27.22 grams. How much greater is the mass of the second co

lora16 [44]

Answer:

The mass is greater by 10.502 grams. If you subtract 27.33 from 16.718, you get 10.502. Therefore, the mass of the second coin is greater than the first coin by 10.502 grams.

3 0

3 years ago

Read 2 more answers

A graphing calculator is recommended. For the limit lim x → 3 (x3 − 4x + 3) = 18 illustrate the definition by finding the larges

alexira [117]

Answer:

Attached is the detailed solution of the problem

∈ = 0.0081 ≈ 0.2

∈ = 0.0042 ≈ 0.1

Step-by-step explanation:

Attached is the detailed solution of the problem

∈ = 0.0081 ≈ 0.2

∈ = 0.0042 ≈ 0.1

A graphing calculator recommended was used to arrive at this solution

6 0

2 years ago