The first thing we must do for this case is to define a variable:
x: number of years
y: total salary
We have then:
For first company:
y = 1500x + 31000
For second company:
y = 2000x + 28500
Equaling both equations we have:
1500x + 31000 = 2000x + 28500
Clearing x:
2000x - 1500x = 31000 - 28500
500x = 2500
x = 2500/500
x = 5
Answer:
It will take for the salaries to be the same about:
x = 5 years
Answer:
Log [x^2 / yz^2]
Step-by-step explanation:
2log(x) =log(x^2)
-log(y) = The minus sign means that you can divide it by first log(x^2)
-2log(z) =log(z^2), and the minus sign again means you can divide it by the first log(x^2)
So, the whole thing can be written like this:
Log(x^2) / [log(y)*log(z^2)], OR:
Log [x^2 / yz^2]
Answer:
the answers for those are number 4 is 150 and 5 is 16%
Step-by-step explanation:
number 4 500 x 30= 15,000
15,000 ÷ 100= 150
number 5 80 x 100=8,000
8,000÷ 500= 16 so 16%
I think it might be B. 48 due to the fact 18 • 48 = 864. I think it would be easier to figure out if there was a picture to go with it. Don’t take my word for it though. Sorry.
Use the pythagorean theorem. You should come out with C. Hope this helps!
