Question

A store opens at 8am. From 8 until 10 customers arrive at a Poisson rate of four an hour. Between 10 and 12, they arrive at a Poisson rate of eight an hour. From 12 to 2, the arrival rate increases steadily from eight per hour at 12 to ten per hour at 2; and from 2 to 5 the arrival rate drops steadily from ten per hour at 2 to four per hour at 5. Determine the probability distribution of the number of customers that enter the store on a given day.

Answer 1

Answer:

The probability distribution of the number of customers that enter the store on a given day is:

$P(x=k)=\frac{57^ke^{-57}}{k!}$

Step-by-step explanation:

To calculate a parameter for the given day, we have to calculate what is the average arrival rate for the day.

This can be done with the data given:

1) From 10 to 12, 8 arrival/hour:  16 expected arrivals in this period

2) From 12 to 2, 8 to 12 arrival/hour (average: 10 arrivals): 20 expected arrivals in this period.

3) From 2 to 5, from 10 to 4 arrival/hour (average: 7 arrivals): 21 expected arrivals in this period.

The total expected arrivals in a day are: 16+20+21=57 arrivals/day.

Then, the probability distribution of the number of customers that enter the store on a given day is:

$P(x=k)=\frac{57^ke^{-57}}{k!}$