Question

In the year 2000 the number of hazardous waste sites in state x was 8 less than twice the number of hazardous waste sites in state Y. Suppose there were 34 such sites in state x. Write and solve an equation to find the number of hazardous waste sites in state y, n, in the year 2000

Answer 1

Answer:

In the year 2000 the number of hazardous waste sites in state y was 21

Step-by-step explanation:

Let

x ----> the number of hazardous waste sites in state x in the year 2000

y ----> the number of hazardous waste sites in state y in the year 2000

we know that

$x=2y-8$ ----> equation A

$x=34$ ----> equation B

Solve the system of equations by substitution

Substitute equation B in equation A

$34=2y-8$

Solve for y

Adds 8 both sides

$34+8=2y$

$42=2y$

Divide by 2 both sides

$y=21$

therefore

In the year 2000 the number of hazardous waste sites in state y was 21