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Ann [662]
3 years ago
14

Stephen Curry plays for the Golden States Warriors and touts a 90% free throw shooting record. If he shot 20 free throws in a ga

me, how many did he miss?
I NEED HELPPPPPPPP PLEASE
Mathematics
1 answer:
oee [108]3 years ago
4 0

He missed 2.

90% of 10 is 9. So he makes 9 shots and misses 1 for every 10 free throws.

So just double that number (1 shot missed) and so you get 2 missed shots

Hope this helps, and please consider marking branliest if this did

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Simiplify.<br> U^2 - 4 / U^2 - 2u
Papessa [141]
Remember
difference of 2 perfect squares
a^2-b^2=(a-b)(a+b)

and the undistributiv propeoryt
ab-ac=a(b-c)

so we have
\frac{u^{2}-4}{u^{2}-2u}
undistribute and factor
\frac{(u-2)(u+2)}{u(u-2)}
cancel out the one ( (u-2)/(u-2)=1)

\frac{(u+2)}{u} is result

3 0
3 years ago
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Help I dont get what to do
Mars2501 [29]

Answer:

  a/(bxy) if b≠0, x≠0, y≠0, x≠y

Step-by-step explanation:

You have correctly simplified the expression. The conditions placed on both the original and simplified forms are that none of the denominator factors may be zero. The denominator factors are b, x, y, and (x-y).

  \dfrac{a}{bxy}\text{ if $b\ne0;$ $x\ne0;$ $y\ne0;$ $x\ne y$}

6 0
2 years ago
What is the value of x?<br><br><br><br> Enter your answer in the box.
Katyanochek1 [597]

The value of x would have to be 90 degrees as it is a right angle.


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3 0
3 years ago
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Pyramid A has a triangular base where each side measures 4 units and a volume of 36 cubic units. Pyramid B has the same height,
omeli [17]

Answer:

The volume of pyramid B is 81 cubic units

Step-by-step explanation:

Given

<u>Pyramid A</u>

s = 4 -- base sides

V = 36 -- Volume

<u>Pyramid B</u>

s = 6 --- base sides

Required

Determine the volume of pyramid B <em>[Missing from the question]</em>

From the question, we understand that both pyramids are equilateral triangular pyramids.

The volume is calculated as:

V = \frac{1}{3} * B * h

Where B represents the area of the base equilateral triangle, and it is calculated as:

B = \frac{1}{2} * s^2 * sin(60)

Where s represents the side lengths

First, we calculate the height of pyramid A

For Pyramid A, the base area is:

B = \frac{1}{2} * s^2 * sin(60)

B = \frac{1}{2} * 4^2 * \frac{\sqrt 3}{2}

B = \frac{1}{2} * 16 * \frac{\sqrt 3}{2}

B = 4\sqrt 3

The height is calculated from:

V = \frac{1}{3} * B * h

This gives:

36 = \frac{1}{3} * 4\sqrt 3 * h

Make h the subject

h = \frac{3 * 36}{4\sqrt 3}

h = \frac{3 * 9}{\sqrt 3}

h = \frac{27}{\sqrt 3}

To calculate the volume of pyramid B, we make use of:

V = \frac{1}{3} * B * h

Since the heights of both pyramids are the same, we can make use of:

h = \frac{27}{\sqrt 3}

The base area B, is then calculated as:

B = \frac{1}{2} * s^2 * sin(60)

Where

s = 6

So:

B = \frac{1}{2} * 6^2 * sin(60)

B = \frac{1}{2} * 36 * \frac{\sqrt 3}{2}

B = 9\sqrt 3

So:

V = \frac{1}{3} * B * h

Where

B = 9\sqrt 3 and h = \frac{27}{\sqrt 3}

V = \frac{1}{3} * 9\sqrt 3 * \frac{27}{\sqrt 3}

V = \frac{1}{3} * 9 * 27

V = 81

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3 years ago
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Marrrta [24]

im pretty sure the answer is 16

Step-by-step explanation:

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