This involves basic arithmetic calculations and simultaneous equations.
Adamu has 25 Cards
Let the following letters represent the number of cards each has;
A: ADAMU
F: FUNKE
S: SHEHU
K: KWAME
T: TANKO
- If adamu gives funke 5 cards, he will have as many as tanko. Thus;
A - 5 = T --- eq 1
- If funke gives adamu 4 cards, he will have as many as kwame. Thus;
A + 4 = K --- eq 2
- Funke and adamu have a total of 13 more cards than the total that kwame and tanko have. Thus;
A + F = K + T + 13 --- eq 3
- Adamu has 2 cards more than what Shehu has. Thus;
A - 2 = S --- eq 4
From online research, the Total Number of cards is 134 and not 133. Thus;
A + F + K + S + T = 134 --- eq 5
Let's put A - 5 = T and A + 4 = K in eq 3 to get;
A + F = (A + 4) + (A - 5) + 13
A + F = 2A + 12
F = 2A - A + 12
F = A + 12
Let's put A - 2 = S ; F = A + 12 ; A - 5 = T and A + 4 = K into eq 5 to get;
A + A + 12 + A + 4 + A - 2 + A - 5 = 134
Simplifying gives;
5A + 9 = 134
5A = 134 - 9
5A = 125
A = 125/5
A = 25
Adamu has 25 Cards
Answer:
hey
Step-by-step explanation:
to calculate perimeter, you require length,breadth
since points are given,find distance between points using distance formulae
<h2>root over (x2-x1)² +(
y2-y1)²</h2>
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<h3>Point H =(6,7)</h3><h3>Point I=(-6,-9)</h3><h3>Point J=(-10,-6)</h3><h3>Point G=2,10)</h3>
Now find distance between HI and IJ
HI gives the distance - length of rectangle
IJ gives the distance - breadth of rectangle
use the formulae ,2(length+breadth) to get perimeter
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HI= root over 144+256= root 400
HI=20
IJ= root over 16+9= root 25
IJ=5
PERIMETER =2(20+5)
2×25
=50
is more than 1/2 so he painted more than 1/2 of his house
|y-9|=6
y-9=6
y-9=-6
y=15
y=3
So, y=15,3
X^2+20x+10 that's the answer
