Answer:
The answer is 53 or Square Root (sqrt) of 2809
Step-by-step explanation:
a^2+b^2=c^2
28^2+45^2=c^2
784+2025=c^2
c^2=sqrt 2809
c = 53
B is the correct answer because it is 11-5
Hope this helps :)
The answer to the question is a
Answer:
y = (-3/2)x + 7
Step-by-step explanation:
3x + 2y = -4 (rearrange to slope intercept form y = mx + b)
2y = -3x - 4
y = (-3/2) x - 2
comparing this to the general form of a linear equation : y = mx + b
we see that slope of this line (and every line that is parallel to this line),
m = -3/2
if we sub this back in to the general form, we get:
y = (-3/2)x + b
We are still missing the value of b. To find this, we are given that the point (4,1) lies on the line. We simply substitute this back into the equation and solve for b.
1 = (-3/2)4 + b
1 = -6 + b
b = 7
substituting this back into the equation:
y = (-3/2)x + 7
<span>The problem is to calculate the angles of the triangle. However, it is not clear which angle you have to calculate, so we are going to calculate all of them
</span>
we know that
Applying the law of cosines
c²=a²+b²-2*a*b*cos C------> cos C=[a²+b²-c²]/[2*a*b]
a=12.5
b=15
c=11
so
cos C=[a²+b²-c²]/[2*a*b]---> cos C=[12.5²+15²-11²]/[2*12.5*15]
cos C=0.694------------> C=arc cos (0.694)-----> C=46.05°-----> C=46.1°
applying the law of sines calculate angle B
15 sin B=11/sin 46.1-----> 15*sin 46.1=11*sin B----> sin B=15*sin 46.1/11
sin B=15*sin 46.1/11-----> sin B=0.9826----> B=arc sin (0.9826)
B=79.3°
calculate angle A
A+B+C=180------> A=180-B-C-----> A=180-79.3-46.1----> A=54.6°
the angles of the triangle are
A=54.6°
B=79.3°
C=46.1°
