Answer:
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Structure L and I are the superior and inferior vena cava. They bring de-oxygenated blood from the body into the right atria.
Answer:
46 and 88° or 67 and 67°
Explanation:
An isosceles triangle has two sides of equal length and one other of a different length;
A triangle with such features also has 2 equal angles and one other;
If we consider that 46° is the angle that is not one of the two equal ones, then we can calculate the other two;
All angles in a triangle sum to 180, so:
180 - 46 = 134
The two remaining angles constitute 134° collectively;
If they are equal, each angle can be found like so:
¹³⁴/₂ = 67
Each of the two equal angles will be 67°;
Alternatively, if 46° is one of the two equal angles, then these two angles will be:
46 × 2 = 92
Then, the remaining angle can be found like so:
180 - 92 = 88
So the angles within the triangle are either:
46, 46 and 88°
or
46, 67 and 67°
Answer: Flower color is an inherited trait, and the F1 and F2 phenotypes of the flowers arising from the pink and white cross can best be explained by another gene product that influences the
phenotypic expression.
Explanation:
Answer:
The proteins will be transported through exocytosis; the carbon dioxide will diffuse through the membrane.
Explanation:
Diffusion is the passive transport of substances down their concentration gradient. The process moves the substances from the region of higher concentration to that of lower concentration. CO2 is a small molecule and does not have any charge. Small, uncharged molecules can diffuse through the lipid bilayer of the cell membrane. Therefore, CO2 can exit a cell by simple diffusion.
On the other hand, proteins are too large to be transported by diffusion across the cell membrane. The proteins are transported by exocytosis. During exocytosis of proteins, membrane-bound vesicles are formed inside the cell. These vesicles carry proteins in them and are called secretory vesicles. The membrane of the vesicles fuse with the cell membrane of cells and transport the proteins outside the cell.