What is the answer_____________________________________________________________________________

A buyer went to the market to buy strawberries. He purchased 120 randomly selected strawberries from a vendor who claimed that n

mafiozo [28]

Answer:

$z=\frac{0.333 -0.25}{\sqrt{\frac{0.25(1-0.25)}{120}}}=2.10$

$p_v =P(z>2.10)=0.018$

At 5% of significance we can conclude that the true proportion of strawberries damage is higher than 0.25

Step-by-step explanation:

Data given and notation

n=120 represent the random sample taken

X=40 represent the number of strawberries damaged

$\hat p=\frac{40}{120}=0.333$ estimated proportion of strawberries damaged

$p_o=0.25$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that no more than 25% of his total harvest of strawberries was damaged.:

Null hypothesis: $p\leq 0.25$

Alternative hypothesis: $p > 0.25$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.333 -0.25}{\sqrt{\frac{0.25(1-0.25)}{120}}}=2.10$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>2.10)=0.018$

At 5% of significance we can conclude that the true proportion of strawberries damage is higher than 0.25

6 0

3 years ago

Sally's average grade in math is a 76 ,but this is not her final grade. Sally takes her Math exam she got a 61 % and the final i

Jobisdone [24]

Answer: 73

I hope this helps and have a wonderful day!!

5 0

3 years ago

Kelly went to a hockey game with her family. They bought 4 bags of cotton candy and 2 souvenir cups and spent $36. Marissa's fam

erik [133]

4b+2c=36, solve for b, subtract 2c from both sides

4b=36-2c divide both sides by 4

b=9-0.5c

Then we are told that:

7b+3c=59, using b=9-0.5c we get:

7(9-0.5c)+3c=59 perform indicated multiplication on left side

63-3.5c+3c=59 combine like terms on left side

63-0.5c=59 subtract 63 from both sides

-0.5c=-4 divide both sides by 0.5

c=8

So each souvenir cup costs $8.

(and each bag of cotton candy is $5)

3 0

3 years ago

HELP ASAP WITH MATH DECIMALS!!! I WILL UPROVE!!!

andriy [413]

Total time taken to attach the wheels and hood to a car = 8.216 + 3.652 = 11.868 seconds

Total time taken to attach good and wheels to 425 cars = 11.868 x 425 = 4925.22 seconds

Ans. 4925.22 seconds

8 0

3 years ago

The probability that house sales will increase in the next 6 months is estimated to be 0.25. The probability that the interest r

marin [14]

Answer:

0.11

Step-by-step explanation:

Probability that house sale will increase = P(A) = 0.25

Probability that interest rate on house loans will go up = P(B) = 0.74

Probability that either house sales will go up or interest rates will go up = P(A or B ) = 0.89

We have to find the probability that neither house sales nor interest rates will increase. This event is the compliment of the event that either house sales will go up or interest rates will go up.

i.e.

Probability that neither house sales nor interest rates will increase = $P(A \cup B)^{c}$

$P(A\cup B)^{c} = 1 - P(A \cup B)$

Using the value of P(A U B), we get:

$P(A\cup B)^{c} = 1 - 0.89\\\\ P(A\cup B)^{c} = 0.11$

The probability that neither house sales nor interest rates will increase during the next 6 months is 0.11

7 0

3 years ago

What is the answer______________________________________________________________________________