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3 years ago

Find the slope and y-intercept -2y=6(5-3x) Please show work

Mathematics

1 answer:

Montano1993 [528]3 years ago

4 0

Y intercept: 0,-15 or just -15
Slope: 9

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How do you solve 2/3 [(5+3) ^-3]

vodka [1.7K]

$\dfrac{2}{3}[(5+3)^{-3}]=\dfrac{2}{3}(8)^{-3}\\\\\text{use}\ a^{-n}=\dfrac{1}{a^n}\\\\=\dfrac{2}{3}\cdot\dfrac{1}{8^3}=\dfrac{2}{3\cdot512}=\dfrac{1}{3\cdot256}=\dfrac{1}{768}$

7 0

3 years ago

Work out the mean. 1, 3, 3. 4. 6, 9, 9

I am Lyosha [343]

1+3+3+4+6+9+9 is 35
7 numbers so divide by 7
35/7 = 5
Mean is 5

8 0

3 years ago

Read 2 more answers

Max walks 6 laps around the track in 30 minutes. How many laps around the track does Max walk in 1 minute

Sunny_sXe [5.5K]

Answer:5

Step-by-step explanation:

6:30 is the ration

6/30 reduced is 1/5

1:5

so its 5

3 0

3 years ago

jasmine took four 20 points quizzes in her math class. if her scores were,18,15,20,15, what was her mean quiz score

g100num [7]

Answer: 17

Step-by-step explanation: ok so first to find the mean you add all the numbers then divide by how many numbers there is so basically 18 plus 15 plus 20 plus 15 then divide by 4 because there is 4 numbers and once you do that it is 17

3 0

3 years ago

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For a certain candy, 20% of the pieces are yellow, 15% are red, 20% are blue, 20% are green, and the rest are brown. a

OLEGan [10]

Answer:

Step-by-step explanation:

Based on the question we are given the percentages of each of the types of candies in the bag except for brown. Since the sum of all the percentages equals 75% and brown is the remaining percent then we can calculate that brown is (100-75 = 25%) 25% of the bag. Now we can show the probabilities of getting a certain type of candy by placing the percentages over the total percentage (100%).

Brown: $\frac{25}{100}$
Yellow or Blue: $\frac{20}{100} +\frac{20}{100} = \frac{40}{100}$ ....add the numerators

Not Green: $\frac{80}{100}$ .... since the sum of all the rest is 80%

Stiped: $\frac{25}{100}$ .... there are 0 striped candies.

Assuming the ratios/percentages of the candies stay the same having an infinite amount of candy will not affect the probabilities. That being said in order to calculate consecutive probability of getting 3 of a certain type in a row we have to multiply the probabilities together. This is calculated by multiplying the numerators with numerators and denominators with denominators.

3 Browns: $\frac{25*25*25}{100*100*100} = \frac{15,625}{1,000,000} = \frac{1.5625}{100}$

the 1st and 3rd are red while the middle is any. We multiply 15% * (total of all minus red which is 85%) * 15% like so.

$\frac{15*85*15}{100*100*100} = \frac{19,125}{1,000,000} = \frac{1.9125}{100}$

None are Yellow: multiply the percent of all minus yellow three times.

$\frac{80*80*80}{100*100*100} = \frac{512,000}{1,000,000} = \frac{51.2}{100}$

At least 1 green: multiply the percent of green by 100% twice, since the other two can by any

$\frac{20*100*100}{100*100*100} = \frac{200,000}{1,000,000} = \frac{20}{100}$

4 0

3 years ago