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3 years ago

Integral of (secx*cos(2x))/(sinx+secx)?

Mathematics

1 answer:

S_A_V [24]3 years ago

5 0

Integral of (secx*cos(2x))/(sinx+secx) = ln (sin (2x) + 2) + c

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20 POINTS!!! FIRST QUESTION TO GET IT CORRECT GETS BRAINLIEST!!

il63 [147K]

Answer:

1320

Step-by-step explanation:

33000/25 = 1320

8 0

3 years ago

Read 2 more answers

Which term best describes the relationship between the two lines?

liraira [26]

Answer:

B Probably shouldn't trust me

Step-by-step explanation:

7 0

4 years ago

Please help me to prove this!

Sophie [7]

Answer: see proof below

Step-by-step explanation:

Given: A + B = C → A = C - B

→ B = C - A

Use the Double Angle Identity: cos 2A = 2 cos² A - 1

→ (cos 2A + 1)/2 = cos² A

Use Sum to Product Identity: cos A + cos B = 2 cos [(A + B)/2] · 2 cos [(A - B)/2]

Use Even/Odd Identity: cos (-A) = cos (A)

Proof LHS → RHS:

LHS: cos² A + cos² B + cos² C

$\text{Double Angle:}\qquad \dfrac{\cos 2A+1}{2}+\dfrac{\cos 2B+1}{2}+\cos^2 C\\\\\\.\qquad \qquad \qquad =\dfrac{1}{2}\bigg(2+\cos 2A+\cos 2B\bigg)+\cos^2 C\\\\\\.\qquad \qquad \qquad =1+\dfrac{1}{2}\bigg(\cos 2A+\cos 2B\bigg)+\cos^2 C$

$\text{Sum to Product:}\quad 1+\dfrac{1}{2}\bigg[2\cos \bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A-2B}{2}\bigg)\bigg]+\cos^2 C\\\\\\.\qquad \qquad \qquad =1+\cos (A+B)\cdot \cos (A-B)+\cos^2 C$

$\text{Given:}\qquad \qquad 1+\cos C\cdot \cos (A-B)+\cos^2C$

$\text{Factor:}\qquad \qquad 1+\cos C[\cos (A-B)+\cos C]$

$\text{Sum to Product:}\quad 1+\cos C\bigg[2\cos \bigg(\dfrac{A-B+C}{2}\bigg)\cdot \cos \bigg(\dfrac{A-B-C}{2}\bigg)\bigg]\\\\\\.\qquad \qquad \qquad =1+2\cos C\cdot \cos \bigg(\dfrac{A+(C-B)}{2}\bigg)\cdot \cos \bigg(\dfrac{-B-(C-A)}{2}\bigg)$

$\text{Given:}\qquad \qquad =1+2\cos C\cdot \cos \bigg(\dfrac{A+A}{2}\bigg)\cdot \cos \bigg(\dfrac{-B-B}{2}\bigg)\\\\\\.\qquad \qquad \qquad =1+2\cos C \cdot \cos A\cdot \cos (-B)$

$\text{Even/Odd:}\qquad \qquad 1+2\cos C \cdot \cos A\cdot \cos B\\\\\\.\qquad \qquad \qquad \quad =1+2\cos A \cdot \cos B\cdot \cos C$

LHS = RHS: 1 + 2 cos A · cos B · cos C = 1 + 2 cos A · cos B · cos C $\checkmark$

5 0

3 years ago

A rectangular fence has a perimeter of 184 feet. The length is four feet less than three times the width. Find the length and th

morpeh [17]

Answer:

lenth = 68 [ft]; width=24 [ft].

Step-by-step explanation:

1) if the length is 'l' and the width - 'w', then it is possible

2) to write the condition 'The length is four feet less than three times the width' as 3w-4=l;

3) to write the given perimeter as 2(w+l)=184.

4) then it is possible to make up the system:

$\left \{ {{2(w+l)=184} \atop {3w-4=l}} \right. \ = > \ \left \{ {{w+l=92} \atop {3w-l=4}} \right. \ = > \ \left \{ {{w=24} \atop {l=68}} \right.$

6 0

2 years ago

In figure shown below, the length of ac is 45 meters. what is the length in meters of bc

alexandr1967 [171]

BC is 21 meters.

2x + 5 + 3x = 45
5x + 5 = 45
5x = 40
X = 8

2(8) + 5 = BC
21 = BC

4 0

4 years ago