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3 years ago

What is the mean absolute deviation definition

Mathematics

1 answer:

Katen [24]3 years ago

3 0

To find the mean absolute deviation of the data, start by finding the mean of the data set.

Find the sum of the data values, and divide the sum by the number of data values.

Find the absolute value of the difference between each data value and the mean: ...

Find the sum of the absolute values of the differences

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Natalka [10]

Answer:

Step-by-step explanation:

x^2.x^1

=9^2.9^1

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81 multiplied by nine

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1 year ago

Find the slope of (0,0) (6,8)

lara31 [8.8K]

Answer:

8/6 or 4/3

Step-by-step explanation:

Rise divided by run. Rise is difference in y values. 8-0=8

Run is difference in x values 6-0=6

Divide 8/6 then simplify. 4/3

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3 years ago

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Vikentia [17]

90 degrees because you go straight down as if it was 1 angle

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3 years ago

How to evaluate this help me out so lost?

Kryger [21]

Answer:

5443

Step-by-step explanation:

Order of Operations: BPEMDAS

Always left to right.

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And we have our answer!

5 0

2 years ago

Anyone know the answer

Artemon [7]

Answer:

$(4\sqrt{3}+6)$

Step-by-step explanation:

Simplify the radical part on by one

$\frac{8\sqrt{6mn}+6\sqrt{8mn}}{2\sqrt{2mn}}$

square root (6) = sqrt(3) * sqrt(2)

square root (8) =sqrt(4)* sqrt(2)= 2sqrt(2)

so given expression becomes

$\frac{8\sqrt{3}\sqrt{2}\sqrt{mn}+6*2\sqrt{2}\sqrt{mn}}{2\sqrt{2mn}}$

$\frac{8\sqrt{3}\sqrt{2mn}+6*2\sqrt{2mn}}{2\sqrt{2mn}}$

$\frac{8\sqrt{3}\sqrt{2mn}+12\sqrt{2mn}}{2\sqrt{2mn}}$

LEts factor out 2 sqrt(2mn) from the top

$\frac{2\sqrt{2mn}(4\sqrt{3}+6)}{2\sqrt{2mn}}$

We cancel out 2sqrt(2mn) at the top and bottom

$(4\sqrt{3}+6)$

6 0

3 years ago