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3 years ago

Can some solve this for me please

Mathematics

1 answer:

lozanna [386]3 years ago

8 0

To solve for y the answer would be $y= 4x^{2} -24x+26$

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Write an algebraic expression to model the given context.Give your answer in simplest form. (please explain)A.) The original pri

babymother [125]

Answer:

The algebraic expression is (P-0.15p) = 0.85p

Step-by-step explanation:

Here, we want to write an algebraic expression to model the situation at hand;

Original price p of an item less a 15% discount

What this mean is that we want to remove a 15% discount from the original price P

That term ‘less’ means we are subtracting

so 15% of p would be;

15/100 * p = 15p/100 = 0.15p

So 15% of P less P is (P-0.15P) = 0.85P

3 0

3 years ago

Help!! Show how you solved it for both thank you

nadezda [96]

Answer:

C and D if im wrong sorry

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Wrote 4093cm in Scientific notation

anygoal [31]

Answer:

4.093*10^3

Step-by-step explanation:

8 0

3 years ago

Find the mean and median of these data: 2, 5, 13, 15, 19, 21.

Maru [420]

The Arithmetic Mean and Median of the given set of data ( 2, 5, 13, 15, 19, 21 ) are 12.5 and 14 respectively.

<h3>What is Arithmetic mean?</h3>

Arithmetic mean is simply the average of a given set numbers. It is determined by dividing the sum of a given set number by their number of appearance.

Mean = Sum total of the number ÷ n

Where n is number of numbers

Median is the middle number in the data set.

Given the sets;

2, 5, 13, 15, 19, 21

n = 6

Mean = Sum total of the number ÷ n

Mean = (2 + 5 + 13 + 15 + 19 + 21) ÷ 6

Mean = 75 ÷ 6

Mean = 12.5

Median is the middle number in the data set.

Median = ( 13 + 15 ) ÷ 2

Median = 14

Therefore, the Arithmetic Mean and Median of the given set of data ( 2, 5, 13, 15, 19, 21 ) are 12.5 and 14 respectively.

Learn more about arithmetic mean here: brainly.com/question/13000783

#SPJ1

3 0

2 years ago

A high-interest savings account pays 5.5% interest compounded annually. If $300 is deposited initially and again at the first of

inessss [21]

That is an annuity and use the attached formula.

Total = 300 * [(1.055)^11 -1] / .055 -300
Total = 300 * 1.8020924036 -1 /.055 -300
Total = 300 * .8020924036 / .055 - 300
Total = 300 * 14.5834982473 -300
Total = 4375.0494741818 -300
Total = 4075.05

4 0

3 years ago