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Veronika [31]
3 years ago
11

In a certain lottery, the winner of the first ticket drawn receives $10. Each succeeding ticket drawn is worth $15 more than the

previous ticket. How much does the holder of the tenth ticket drawn receive?
Mathematics
1 answer:
kifflom [539]3 years ago
4 0
The value of each winning ticket is an arithmetic series in which T (n) = -5 + 15n or $5 (3n-1). The first winner is 5 (3x1 - 1) = $10. The second winner is 5 (3x2 - 1) = $25. The tenth ticket wins $5 (3x10 - 1) = $5 (29) = $145.
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\bf \cfrac{A}{B}=\cfrac{3}{6}\implies \cfrac{A}{B}=\cfrac{1}{2}\implies 2A=\boxed{B}
\\\\[-0.35em]
~\dotfill\\\\
A+B=90\implies A+\boxed{2A}=90\implies 3A=90\\\\\\ A=\cfrac{90}{3}\implies \blacktriangleright A=30 \blacktriangleleft
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
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