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fenix001 [56]
4 years ago
11

If 500 people were surveyed, how many chose English as their favorite subject?

Mathematics
2 answers:
alexira [117]4 years ago
8 0

Answer:

I think the first questions answer is 30 people. And the second questions answer is 75

Step-by-step explanation:

To determine how many students voted for Math, you must remove the votes from the 195 students that have been counted, from the total 270 who voted. So, 270 − 195 = 75 students voted for Math as their favorite subject.

For the first question I just found out what 6% of 500 is.

svp [43]4 years ago
3 0

Good evening ,

Answer:

<h2>(1) The number of people that chose English as their favorite subject is 30</h2><h2>(2)The number of people that were surveyed is 600.</h2>

Step-by-step explanation:

The number of people that chose English as their favorite subject

500×6% = 500×(6÷100) = (500×6)÷100 = 3 000÷100 = 30

The number of people that were surveyed

270×(100÷45) = (270×100)÷45 = 27 000÷45 = 600.

:)

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What is the value of y?
nata0808 [166]

Answer: y = 16.5

Step-by-step explanation:

We would apply Pythagoras theorem which is expressed as

Hypotenuse² = opposite side² + adjacent side²

Considering triangle BCD,

BD² = 14² - 8²

BD² ° 196 - 64 = 132

BD = √132

Considering triangle ABD,

AB² = BD² + y²

AB² = (√132)² + y²

AB² = 132 + y²- - - - - - - - - - 1

Considering triangle ABC,

(8 + y)² = AB² + BC²

(8 + y)² = AB² + 14²

(8 + y)² = AB² + 196

AB² = (8 + y)² - 196- - - - - - - -2

Substituting equation 1 into equation 2, it becomes

132 + y² = (8 + y)² - 196

y² - (8 + y)² = - 196 - 132

y² - (64 + 16y + y²) = - 328

y² - 64 - 16y - y2 = - 328

- 16y = - 328 + 64

- 16y = - 264

y = - 264/- 16

y = 16.5

6 0
3 years ago
Use the WeierstrassM-test to show that each of the following series converges uniformly on the given domain:
ryzh [129]

Answer:

Step-by-step explanation:

Given a series \sum_{k=1}^\infty f(z), the Weierstrass M-test tell us that if we find a sequence of positive numbers M_n such that |f(z)|\leq M_n in a certain domain D, and the series \sum_{n=1}^\infty M_k converges, then the series \sum_{k=1}^\infty f_k(z) converges uniformly in the domain D.

So, our objective is to find the so called sequence M_k. The main idea is to bound the sequence of functions \frac{z^k}{z^k + 1}.

Now, notice that the values of z are always positive, so z^k is always positive, so z^k+1\geq 1 for all values of z in \overline{D}. Then,

\Big| \frac{z^k}{z^k + 1}\Big| \leq z^k,

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Moreover, as z is in the interval [0,r], we have that z\leq r and as consequence |z^k|\leq r^k. With this in addition to the previous bound we obtain

\Big| \frac{z^k}{z^k + 1}\Big| \leq |z^k|\leq r^k.

With this, our sequence is M_k = r^k and the corresponding series is \sum_{k=1}^\infty r^k, which is a geometric series with ratio less than 1, hence it is convergent.

Then, as consequence of Weierstrass M-test we have the uniform convergence of the series in the given domain.

6 0
3 years ago
The Garcias have​ $12,000 in a saving account. The bank pays​ 3.5% interest on saving​ accounts, compounded monthly. Find the ba
LUCKY_DIMON [66]
The formula is
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Hope it helps!
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luda_lava [24]
Are these the answer choices. If so I would say D
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k0ka [10]

Answer:

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Step-by-step explanation:

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