Question

Four students are verifying that

Answer 1

Answer:

Option D is correct.

Step-by-step explanation:

We have been given:

$x^2+x-12$

$x^2+4x-3x-12$

$x(x+4)-3(x+4)$

$(x-3)(x+4)$

Hence, the zeroes are: -4 and 3

4(-3)=-12

And -3+4=1

Hence, Latisha is correct.

Therefore, Option D is correct.

Answer 2

I am gonna have to go with Latisha's answer.

(x - 3)(x + 4) = x^2 + 4x - 3x - 12 = x^2 + x - 12.......and 4(-3) = -12, -3 + 4 = 1....and the factors are correct