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Alisiya [41]
3 years ago
5

I need help fast what is 9m−​(3+7​m) simplified?

Mathematics
1 answer:
iogann1982 [59]3 years ago
4 0

Answer:

Simplifying 9m + -3 + -7m = 0

Reorder the terms: -3 + 9m + -7m = 0

Combine like terms: 9m + -7m = 2m -3 + 2m = 0 Solving -3 + 2m = 0

Solving for variable 'm'. Move all terms containing m to the left, all other terms to the right.

Add '3' to each side of the equation. -3 + 3 + 2m = 0 + 3 Combine like terms: -3 + 3 = 0 0 + 2m = 0 + 3 2m = 0 + 3 Combine like terms: 0 + 3 = 3 2m = 3

Divide each side by '2'. m = 1.5

Step-by-step explanation:

Hope this helps :)

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Answer:

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Step-by-step explanation:

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3 years ago
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Jill sold half of her comic books and then bought sixteen more. She now has 36. With how many did she begin?
Alex777 [14]

Answer:

\frac{1}{2}x + 16 = 36

40 comic books

Step-by-step explanation:

Let x be the Jill comic books.

Given:

Jill sold half of her comic books and then bought sixteen more. She now has 36.

\frac{1}{2}\ (Jill\ books) + 16\ more\ books = 36

\frac{1}{2}\ (x) + 16 = 36

\frac{1}{2}x + 16 = 36

Therefore the algebraic equation of the given statement.

\frac{1}{2}x + 16 = 36--------(1)

Now we solve above equation for x.

Subtract by 16 both side of the equation 1.

\frac{1}{2}x + 16 -16 = 36 -16

\frac{1}{2}x = 20

Multiply by 2 both side of the above equation.

2\times \frac{1}{2}x =2\times 20

x = 40

Therefore, Jill had 40 comic books.

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Solve for X. Round to the nearest tenth of a degree, if necessary.
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the initial vertical velocity of a rocket shot straight up is 42 meters per second. How long does it take for the rocket to retu
Snowcat [4.5K]
It takes 4.3 seconds for the rocket to return to earth.

The equation is:
0=-9.8t^2+v_0t+h_0
where -9.8m/sec² is the acceleration due to gravity, v₀ is the initial velocity, and h₀ is the initial height.  We will go from the assumption that the rocket is launched from the ground, so h₀=0, and we are told that the initial velocity, v₀, is 42.  This gives us:

0=-9.8t^2+42t

We will use the quadratic formula to solve this.  The quadratic formula is:
x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Plugging in our information we have:
t=\frac{-42\pm \sqrt{42^2-4(-9.8)(0)}}{2(-9.8)}
\\
\\=\frac{-42\pm \sqrt{1764-0}}{-19.6}
\\
\\=\frac{-42\pm \sqrt{1764}}{-19.6}
\\
\\=\frac{-42\pm 42}{-19.6}=\frac{-42-42}{-19.6} \text{ or } \frac{-42+42}{-19.6}
\\
\\=\frac{-84}{-19.6}\text{ or }\frac{0}{-19.6}
\\
\\=4.3\text{ or }0

x=0 is when the rocket is launched; x=4.3 is when the rocket lands.
8 0
3 years ago
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