Step-by-step explanation:
Answer:
FG = 31
Step-by-step explanation:
By applying mid-segment theorem in the given trapezoid,
Segment joining midpoints of the nonparallel sides is parallel and measure the half of the sum of parallel sides.
FG = ![\frac{1}{2}[UV+TW]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5BUV%2BTW%5D)
(7x - 4) = ![\frac{1}{2}[(6x-6)+38]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5B%286x-6%29%2B38%5D)
2(7x - 4) = 6x + 32
14x - 8 = 6x + 32
14x - 6x = 32 + 8
8x = 40
x = 5
Therefore, FG = (7x - 4)
= 7(5) - 4
= 31
Well so 15000-2000 leaves 13000kgs of available weight allowed. Then 13000 divided by 1500 we get around 8.67 cubicmeters of gravel to be allowed to be lifted safely.
Hey there mate ;)
Note that the quadratic function
A(x) = x(100-2x) gives the area.
Now, this equation is equivalent to:
A(x) = 100x - 2x²
To find maximum value of A, we first find the derivative of the given function:

Now find the critical value by setting dA/dx=0, that is:-

Solving for x, we get:

Hence, the critical point is x=25
Now, Find 2nd derivative to check if the equation has maximum value:

Noting that the 2nd derivative is negative, hence, we have a maximum value. Infact, the maximum value in this case is when the value of x = 25.
The maximum area is therefore,

→ The Correct answer is:

The third quartile of this data set is B. 24.