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Rom4ik [11]
3 years ago
8

)^{2}+5\sqrt({x} +2)" alt="f(x)=2(x)^{2}+5\sqrt({x} +2)" align="absmiddle" class="latex-formula">
f(2) = ___

IM LITERALLY BEGGING SOMEONE TO ANSWER THIS AS FAST AS POSSIBLE
I WILL GIVE BRAINLIEST :D
Mathematics
1 answer:
Delvig [45]3 years ago
7 0

Answer:

f(2)=18

Step-by-step explanation:

f(x)=2(x)^2+5 \sqrt{x+2}\\f(2)=2(2)^2+5 \sqrt{2+2}\\=2*4+5\sqrt{4} \\=8+5*2\\=8+10\\=18

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K - 263.48 = 381.09 solve this equation
Sedbober [7]
K-263.48=381.09
we add 263.48 on both sides
k=644.57
7 0
4 years ago
Read 2 more answers
Find the equation of the line<br> Slope =4/3<br> y-intercept =-5
AlladinOne [14]

Answer:

y=4/3x - 5

Step-by-step explanation:

5 0
3 years ago
Tim and Tom are painters. Tim and Tom are painting a crate. Tom paints 10 sq ft per minute. They painted a particular crate in 1
slava [35]
Tom-------------- >10 sq ft per minute

Tim------------------- >3.5*10=35 sq ft per minute

 Both painters (10+35)=45 sq ft per minute

 let's assume a cubic unit crate----------> V1=1*1*1=1 feet3

<span>the total surface of the cube is S1=6*(1*1)=6 </span>sq ft

 if the volume of the cube increases twice 

V2=2 feet3 ------------------- >    2=x*x*x------------- >x=2^(1/3)

And the S2=6*(2^(1/3)*<span> 2</span>^(1/3)=9.5244 sq ft

V2/V1=9.5244/6=1.5874

Therefore

If Tim and Tom----------------------- > take 1 day----------- > to paint a crate V1

For the crate V2------------- > take 1.5874 days 

assuming an 8-hour work day

 0.5874*8=4.70 hr-------------- > 4 h 42 min

 The answer is 1 day 4h 42 min

6 0
4 years ago
0 0
morpeh [17]

Answer:

a) slope / m = 3

b) y-intercept / b = 0

c) Proportional

Step-by-step explanation:

a)

( y1 - y2 ) / ( x1 - x2 )

( 6 - 12 ) / ( 2 - 4 )

( -6 ) / ( -2 )

6 / 2

3

b)

y = mx + b

6 = 3(2) + b

6 = 6 + b

0 = b

c)

Proportional is when it crosses origin ( 0, 0 ).

Not proportional is when it does not cross origin.

Hopefully this helps!

Brainliest please?

6 0
2 years ago
Find the general solution of {y}''-3y=8e^{3t}+4sin(t) .
babunello [35]

Answer:

y(x)=C_1e^{\sqrt3t}+C_2e^{-\sqrt3t}-\frac{4}{3}e^{3t}-sint

Step-by-step explanation:

We are given that linear differential equation

y''-3y=8e^{3t}+4 sint

Auxillary equation

D^2-3=0

D=\pm \sqrt3

C.F=C_1e^{\sqrt3t}+C_2e^{-\sqrt3}

P.I=\frac{8e^{3t}+4sin t}{D^2-3}

P.I=\frac{8e^{3t}}{9-3}+4\frac{sint }{-1-3}

P.I=e^{ax}{\phi (D+a)} and P.I=\frac{sinax}{(\phi D)}where D square is replace by - a square

P.I=-\frac{4}{3}e^{3t}- sint

Hence, the general solution

G.S=C.F+P.I

y(x)=C_1e^{\sqrt3t}+C_2e^{-\sqrt3t}-\frac{4}{3}e^{3t}-sint

3 0
3 years ago
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