<img src="https://tex.z-dn.net/?f=f%28x%29%3D2%28x%29%5E%7B2%7D%2B5%5Csqrt%28%7Bx%7D%20%2B2%29" id="TexFormula1" title="f(x)=2(x

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3 years ago

)^{2}+5\sqrt({x} +2)" alt="f(x)=2(x)^{2}+5\sqrt({x} +2)" align="absmiddle" class="latex-formula">
f(2) = ___

IM LITERALLY BEGGING SOMEONE TO ANSWER THIS AS FAST AS POSSIBLE
I WILL GIVE BRAINLIEST :D

Mathematics

1 answer:

Delvig [45]3 years ago

7 0

Answer:

f(2)=18

Step-by-step explanation:

$f(x)=2(x)^2+5 \sqrt{x+2}\\f(2)=2(2)^2+5 \sqrt{2+2}\\=2*4+5\sqrt{4} \\=8+5*2\\=8+10\\=18$

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Chase buys a bag of cookies that contains 6 chocolate chip cookies, 6 peanut butter cookies, 6 sugar cookies and 6 oatmeal cooki

Over [174]

Answer:

0.0652173

Step-by-step explanation:

Given that :

6 chocolate chip cookies

6 peanut butter cookies

6 sugar cookies

6 oatmeal cookies

Total number of cookies purchased = (6+6+6+6) = 24

Probability, P= required outcome /total possible outcomes

This is a selection without replacement probability problem :

P(peanut butter cookies) = 6/24 = 1/4

Then ;

P(chocolate chip cookie) = 6/23

Hence,

P(peanut butter cookies then chocolate chip cookie) = 1/4 * 6/23 = 0.0652173

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2 years ago

Anyone can help me solve this equation using cross multiplying

Natali5045456 [20]

9514 1404 393

Answer:

x = 1 or 5

Step-by-step explanation:

The notion of "cross-multiplying" is the idea that the numerator on the left is multiplied by the denominator on the right, and the numerator on the right is multiplied by the denominator on the left. This looks like ...

$\displaystyle \frac{x-1}{7}=\frac{2x-2}{3x-1}\ \longrightarrow\ (x-1)(3x-1)=(7)(2x-2)$

Then the solution proceeds by eliminating parentheses, and solving the resulting quadratic equation.

$3x^2-4x+1=14x-14\\\\3x^2-18x+15=0\qquad\text{subtract $14x-14$}\\\\x^2-6x+5=0 \qquad\text{divide by 3}\\\\(x-1)(x-5)=0\qquad\text{factor}\\\\x\in\{1,5\}$

_____

Comment on "cross multiply"

Like a lot of instructions in Algebra courses, the idea of "cross multiply" describes what the result looks like. It doesn't adequately describe how you get there. The one and only rule in solving Algebra problems is "whatever is done to one side of the equation must also be done to the other side of the equation." If you multiply one side by one thing and the other side by a different thing, you are violating this rule.

What looks like "cross multiply" is really "multiply by the product of the denominators and cancel like terms from numerator and denominator." Here's what that looks like with the intermediate steps added.

$\displaystyle \frac{x-1}{7}=\frac{2x-2}{3x-1}\\\\\frac{x-1}{7}\times7(3x-1)=\frac{2x-2}{3x-1}\times7(3x-1)\\\\(x-1)(3x-1)=(2x-2)(7)\qquad\textit{looks like}\text{ cross multiply}$

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2 years ago

Suppose a spider was able to create one thread that would extend from the top-right back corner of a room to the bottom-left fro

NNADVOKAT [17]

Answer:

d^2 = 30^2 + 12^2

e^2 = d^2 + 8^2

e^2 = 30^2 + 12^2 + 8^2

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3 years ago

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Express 1400 as a product of its prime factors in index form

exis [7]

Answer:

$2^3 X5^2 X7$

Step-by-step explanation:

Given the number: 1400

A number is said to be prime when it can only be divided by 1 and itself.

We can express 1400 as a product of its prime numbers by gradually decomposing it into smaller units.

$1400=14X100\\14=2X7\\100=10X10=2X5X2X5\\$Therefore:\\1400=2 X 7 X 2 X 5 X 5 X 5\\Reorganising\\1400=2 X 2 X 2 X 5 X 5 X 7\\Therefore, 1400 expressed as a product of its prime factors is:\\1400=2^3 X5^2 X7$

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3 years ago

DOES ANYONE UNDERTAND THIS? IF SO PLEASE HELP

Nana76 [90]

The sides must be equal otherwise BC and AD wouldn't be parallel. So
12x-6 = 2x+7
10x = 13
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3 years ago