<img src="https://tex.z-dn.net/?f=f%28x%29%3D2%28x%29%5E%7B2%7D%2B5%5Csqrt%28%7Bx%7D%20%2B2%29" id="TexFormula1" title="f(x)=2(x

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3 years ago

)^{2}+5\sqrt({x} +2)" alt="f(x)=2(x)^{2}+5\sqrt({x} +2)" align="absmiddle" class="latex-formula">
f(2) = ___

IM LITERALLY BEGGING SOMEONE TO ANSWER THIS AS FAST AS POSSIBLE
I WILL GIVE BRAINLIEST :D

Mathematics

1 answer:

Delvig [45]3 years ago

7 0

Answer:

f(2)=18

Step-by-step explanation:

$f(x)=2(x)^2+5 \sqrt{x+2}\\f(2)=2(2)^2+5 \sqrt{2+2}\\=2*4+5\sqrt{4} \\=8+5*2\\=8+10\\=18$

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