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Korvikt [17]
3 years ago
14

Choose the solution to this inequality.

Mathematics
1 answer:
natita [175]3 years ago
3 0

Answer:

C

Step-by-step explanation:

If you used the inequality in C, b being able to be as high as -23, it would make 72 is greater than or equal to 72, which is true.

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What are the solutions of the equation x² = 49
olga55 [171]
To find x you do √49=x
5 0
3 years ago
7 pens and 2 pencils cost 22
Romashka [77]

Pen : $3

Pencil : $0.50

4 0
3 years ago
The wankel T. rex is in display at the Smithsonian Washington DC scientists estimate that it was 18 years old when it died. Abou
Phoenix [80]

Answer:

About 5,000 kilograms

Step-by-step explanation:

Look on the x-axis for 18 years. Then go up to where the plotted line is on 18 years to find the y-axis or the mass.

5 0
2 years ago
Annual starting salaries in a certain region of the U. S. for college graduates with an engineering major are normally distribut
defon

Answer:

0.8665 = 86.65% probability that the sample mean would be at least $39000

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean $39725 and standard deviation $7320.

This means that \mu = 39725, \sigma = 7320

Sample of 125:

This means that n = 125, s = \frac{7320}{\sqrt{125}} = 654.72

The probability that the sample mean would be at least $39000 is about?

This is 1 subtracted by the pvalue of Z when X = 39000. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{39000 - 39725}{654.72}

Z = -1.11

Z = -1.11 has a pvalue of 0.1335

1 - 0.1335 = 0.8665

0.8665 = 86.65% probability that the sample mean would be at least $39000

4 0
2 years ago
Solve each inequality:
Talja [164]
It should be the answers if not sorry
Answer:
A) X<1
B) X>7
C)X<6
D)X>-3
6 0
2 years ago
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