All categories

3 years ago

Please help ASAP. Need it for homework

Mathematics

1 answer:

zmey [24]3 years ago

8 0

Reliable taxis : for 30 miles
C = 1.5x....x = 30
C = 1.5(30)
C = 45

speedy taxis : for 30 miles
C = 1.1x + 11.5....x = 30
C = 1.1(30) + 11.5
C = 33 + 11.5
C = 44.5

city taxis : for 30 miles
C = 1.25x + 8...x = 30
C = 1.25(30) + 8
C = 37.5 + 8
C = 45.5

the cheapest company is : speedy taxis

You might be interested in

Use the long division method to find the result when 23 – 702 +93 – 11 is divided by 2x 1. If there is a remainder, express the

Bogdan [553]

Answer:

gdjtdigdigxigxig

Step-by-step explanation:

hzhfsitdutxigxiycoyxigxitxi

3 0

3 years ago

Audrey, an astronomer is searching for extra-solar planets using the technique of relativistic lensing. Though there are believe

Stolb23 [73]

Answer:

Step-by-step explanation:

The model $N (t)$ , the number of planets found up to time $t$ , as a Poisson process. So, the $N (t)$ has distribution of Poison distribution with parameter $(\lambda t)$

The mean for a month is, $\lambda = \frac{1}{3}$ per month

$E[N(t)]= \lambda t\\\\=\frac{1}{3}(24)\\\\=8$

(Here. t = 24)

For Poisson process mean and variance are same,

$Var[N (t)]= Var[N(24)]\\= E [N (24)]\\=8$

(Poisson distribution mean and variance equal)

The standard deviation of the number of planets is,

$\sigma( 24 )] =\sqrt{Var[ N(24)]}=\sqrt{8}= 2.828$

For the Poisson process the intervals between events(finding a new planet) have independent exponential distribution with parameter $\lambda$ . The sum of $K$ of these independent exponential has distribution Gamma $(K, \lambda)$ .

From the given information, $k = 6$ and $\lambda =\frac{1}{3}$

Calculate the expected value.

$E(x)=\frac{\alpha}{\beta}\\\\=\frac{K}{\lambda}\\\\=\frac{6}{\frac{1}{3}}\\\\=18$

(Here, $\alpha =k$ and $\beta=\lambda$ )

Calculate the probability that she will become eligible for the prize within one year.

Here, 1 year is equal to 12 months.

P(X ≤ 12) = (1/Г (k)λ^k)(x)^(k-1).(e)^(-x/λ)

$=\frac{1}{Г (6)(\frac{1}{3})^6}(12)^{6-1}e^{-36}\\\\=0.2148696\\=0.2419\\=21.49%$

Hence, the required probability is 0.2149 or 21.49%

5 0

3 years ago

Need help with equations with variables on both sides, giving 100 points, tysm if you help :) 6 (2x-4) = 8(x +2) A. 3 B. 10 C. 2

scoundrel [369]

Answer:

B. 10

C. All real numbers.

Step-by-step explanation:

6 (2x-4) = 8(x + 2)

Distribute the numbers outside of the factors:

12x - 24 = 8x + 16

Subtract both sides by '8x'

12x - 8x - 24 = 8x - 8x + 16

4x - 24 = 16

Add '24' to both sides:

4x = 40

Divide both sides by 4:

x = 10. Therefore, <u>B. 10</u> is the correct answer.

3(4p - 2) = -6(1 - 2p)

Distribute the numbers similarly to the example before:

12p - 6 = -6 + 12p

Subtract '12p' from both sides:

12p - 12p -6 = -6 + 12p - 12p

0 -6 = -6

Add '6' to both sides:

0 - 6 + 6 = -6 + 6

0 = 0

Therefore, the solution consists of <u>all real numbers.</u>

3 0

3 years ago

i see two things at the mall one shirt is 32$ and is 70% off and the 2nd shirt is 33$ and is 71% percent off which is a better d

Lemur [1.5K]

They would be an equal price

8 0

3 years ago

Ship A receives a distress signal from the north, And ship B receives a distress signal from the same vessel from the southeast.

11Alexandr11 [23.1K]

The coordinates of Ship A and B are missing, so i have attached it

Answer:

The vessel in distress is located at the coordinate (1, 2)

Step-by-step explanation:

The coordinates attached shows that;

Coordinates of A are (3, 4) while that of B are (1, 1).

We are told that Ship A receives a distress signal from the north, And ship B receives a distress signal from the same vessel from the southeast.

Now, from the image attached, If we imagine extending the line of ship A that is getting distress signal from southeast and also same thing for ship B that is getting signal from north,we'll discover that the lines intersect at a point with co-ordinates of approximately; (1, 2)

8 0

3 years ago