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3 years ago

15

Does someone knows the correct answer?? I think is d but I don’t know

2 answers:

kodGreya [7K]3 years ago

3 0

Answer:

I think you are right

Step-by-step explanation:

MrMuchimi3 years ago

3 0

Answer:

YES I AM PRETTY SURE ITs :D GOOD LUCK HAVE A GREAT DAY

Step-by-step explanation:

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You need to buy 200 treats for a party. You can buy cookies at $ 0.80 each or muffins at $1.60 each. Your goal is to spend $200

Agata [3.3K]

You should buy cookies, because .80 x200=160 , which is less than $200

4 0

3 years ago

Stan had 15 apples and gave 10 to his sister. If he had 21 apples and wanted to give the same percentage to his sister, how many

DENIUS [597]

10 x

15 100

15x=1000

x= 66.6666

ANSWER IS 14

8 0

3 years ago

Washing powder cost 12.87 for 9 kg. hwo much does 1 kg cost to the nearst cent

Goryan [66]

Answer:

hard

Step-by-step explanation:

I don't know because I have never learnt these things

5 0

3 years ago

Read 2 more answers

1. S(–4, –4), P(4, –2), A(6, 6) and Z(–2, 4) a) Apply the distance formula for each side to determine whether SPAZ is equilatera

Aleksandr [31]

Answer:

a) SPAZ is equilateral.

b) Diagonals SA and PZ are perpendicular to each other.

c) Diagonals SA and PZ bisect each other.

Step-by-step explanation:

At first we form the triangle with the help of a graphing tool and whose result is attached below. It seems to be a paralellogram.

a) If figure is equilateral, then SP = PA = AZ = ZS:

$SP = \sqrt{[4-(-4)]^{2}+[(-2)-(-4)]^{2}}$

$SP \approx 8.246$

$PA = \sqrt{(6-4)^{2}+[6-(-2)]^{2}}$

$PA \approx 8.246$

$AZ =\sqrt{(-2-6)^{2}+(4-6)^{2}}$

$AZ \approx 8.246$

$ZS = \sqrt{[-4-(-2)]^{2}+(-4-4)^{2}}$

$ZS \approx 8.246$

Therefore, SPAZ is equilateral.

b) We use the slope formula to determine the inclination of diagonals SA and PZ:

$m_{SA} = \frac{6-(-4)}{6-(-4)}$

$m_{SA} = 1$

$m_{PZ} = \frac{4-(-2)}{-2-4}$

$m_{PZ} = -1$

Since $m_{SA}\cdot m_{PZ} = -1$ , diagonals SA and PZ are perpendicular to each other.

c) The diagonals bisect each other if and only if both have the same midpoint. Now we proceed to determine the midpoints of each diagonal:

$M_{SA} = \frac{1}{2}\cdot S(x,y) + \frac{1}{2}\cdot A(x,y)$

$M_{SA} = \frac{1}{2}\cdot (-4,-4)+\frac{1}{2}\cdot (6,6)$

$M_{SA} = (-2,-2)+(3,3)$

$M_{SA} = (1,1)$

$M_{PZ} = \frac{1}{2}\cdot P(x,y) + \frac{1}{2}\cdot Z(x,y)$

$M_{PZ} = \frac{1}{2}\cdot (4,-2)+\frac{1}{2}\cdot (-2,4)$

$M_{PZ} = (2,-1)+(-1,2)$

$M_{PZ} = (1,1)$

Then, the diagonals SA and PZ bisect each other.

8 0

3 years ago

Here's a graph of a linear function. Write the

Natalija [7]

Answer:

$\large\boxed{y=\dfrac{1}{4}x+3}$

Step-by-step explanation:

The slope-intercept form of an equation of a line:

$y=mx+b$

m - slope

b - y-intercept → (0, b)

From the graph we have the points (4, 4) and (0, 3) → b = 3.

We have the equation:

$y=mx+3$

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

Put the coordinates of the points:

$m=\dfrac{3-4}{0-4}=\dfrac{-1}{-4}=\dfrac{1}{4}$

Finally we have:

$y=\dfrac{1}{4}x+3$

7 0

3 years ago