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RUDIKE [14]
3 years ago
10

A card is drawn from a standard deck of 52 playing cards. Find the probability that the card is a black card given that it is an

ace.
Mathematics
1 answer:
Pavlova-9 [17]3 years ago
5 0

probability of getting black card an ace =2/52=1/26

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>

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3 years ago
If $2940 is invested at 3.2% compounded quarterly, how much is in the account after 8 years?
tino4ka555 [31]

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The future value is $3793.776

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FV = PV(1 + \frac{r}{n})^{nt

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FV =2940 * (1 + \frac{3.2\%}{4})^{4*8

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3 0
2 years ago
The vertices of ∆ABC are A(2, 8), B(16, 2), and C(6, 2). what is the perimeter and area in square units
ad-work [718]
Check the picture below.

the triangle has that base and that height, recall that A = 1/2 bh.

now as for the perimeter, you can pretty much count the units off the grid for the segment CB, so let's just find the lengths of AC and AB,

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&A&(~ 2 &,& 8~) &#10;%  (c,d)&#10;&C&(~ 6 &,& 2~)&#10;\end{array}~~~ &#10;%  distance value&#10;d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}&#10;\\\\\\&#10;AC=\sqrt{(6-2)^2+(2-8)^2}\implies AC=\sqrt{4^2+(-6)^2}&#10;\\\\\\&#10;AC=\sqrt{16+36}\implies AC=\sqrt{52}\implies AC=\sqrt{4\cdot 13}&#10;\\\\\\&#10;AC=\sqrt{2^2\cdot 13}\implies AC=2\sqrt{13}

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&A&(~ 2 &,& 8~) &#10;%  (c,d)&#10;&B&(~ 16 &,& 2~)&#10;\end{array}\\\\\\&#10;AB=\sqrt{(16-2)^2+(2-8)^2}\implies AB=\sqrt{14^2+(-6)^2}&#10;\\\\\\&#10;AB=\sqrt{196+36}\implies AB=\sqrt{232}\implies AB=\sqrt{4\cdot 58}&#10;\\\\\\&#10;AB=\sqrt{2^2\cdot 58}\implies AB=2\sqrt{58}

so, add AC + AB + CB, and that's the perimeter of the triangle.

8 0
3 years ago
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