Complete question:
The growth of a city is described by the population function p(t) = P0e^kt where P0 is the initial population of the city, t is the time in years, and k is a constant. If the population of the city atis 19,000 and the population of the city atis 23,000, which is the nearest approximation to the population of the city at
Answer:
27,800
Step-by-step explanation:
We need to obtain the initial population(P0) and constant value (k)
Population function : p(t) = P0e^kt
At t = 0, population = 19,000
19,000 = P0e^(k*0)
19,000 = P0 * e^0
19000 = P0 * 1
19000 = P0
Hence, initial population = 19,000
At t = 3; population = 23,000
23,000 = 19000e^(k*3)
23000 = 19000 * e^3k
e^3k = 23000/ 19000
e^3k = 1.2105263
Take the ln
3k = ln(1.2105263)
k = 0.1910552 / 3
k = 0.0636850
At t = 6
p(t) = P0e^kt
p(6) = 19000 * e^(0.0636850 * 6)
P(6) = 19000 * e^0.3821104
P(6) = 19000 * 1.4653739
P(6) = 27842.104
27,800 ( nearest whole number)
Answer:8
Step-by-step explanation;Since you want to find the density but you already have the mass you do the inverse operation and divdie 56 by 7 and get 8.
1 ÷ 4 1/4 so one lap is a quarter of a mile meaning 3 laps is 3/4 of a mile
Answer:
2/15
Step-by-step explanation:
1/3-1/5
5/15-3/15
= 2/15
The correct answer to your question is going to be option C. if we look at the equation 4x + 7 = 31, we can see that 4x stands for a number that changed depending on how much of something x can be. the 7 in the equation stands for something doesnt change depending upon variables how much or how little x will be. knowing this, if we look at option C we read that each phone case cost $7 while $4 is how much it costs to ship. since this problem is about how many $4 phone cases Taliba can get, C would incorrect because they say that $7 is the post of each phone case.
let me know if you have any further questions
:)
