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mylen [45]
4 years ago
12

A solid has a high to very high melting point, great hardness , and poor electrical conduction, this is an_______solid.

Chemistry
2 answers:
xxMikexx [17]4 years ago
8 0
A solid that has a high to very high melting point, great hardness, and poor electrical conduction is an : E. Ionic solid

Ionic solid consist of oppositely charge ions. One of the example of Ionic solid is salt (NaCl)

hope this helps
Scrat [10]4 years ago
5 0
A solid has a high to very high melting point, great hardness , and poor electrical conduction, this is a <span>covalent network </span>solid.
A network<span> solid</span><span> is a chemical compound in which the atoms are bonded by </span>covalent<span> bonds.

</span><span>d. covalent network</span>
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Classify each process as either physical or a chemical change.
Dafna11 [192]

Answer:

I think they are all correct

7 0
3 years ago
How many moles of solve (Ag) are equivalent to 68.3g Ag
Zina [86]
Moles Ag = 68.3 g / 107.868 g/mol=0.633
5 0
4 years ago
A 1.0 M solution of a compound with 2 ionizable groups (pKa's = 6.2 and 9.5; 100 mL total) has a pH of 6.8. If a biochemist adds
juin [17]

Answer:

pH = 9,32

Explanation:

The compound with 2 ionizable groups has the following equilibriums:

H₂M ⇄ HM⁻ + H⁺ pka = 6,2

HM⁻ ⇄ M²⁻ + H⁺ pka = 9,5

The reaction of M²⁻ with HCl is:

M²⁻ + HCl → HM⁻ + Cl⁻

The moles of M²⁻ are:

0,100L×1,0M = 0,1moles

And moles of HCl are:

0,060L×1,0M = 0,06moles

That means that moles of M²⁻ will be 0,1-0,06 = 0,04mol and moles of HM⁻ will be the same than HCl, 0,06mol

Using Henderson-Hasselbalch formula:

pH = pka + log₁₀ [M²⁻] / [HM⁻]

Replacing:

pH = 9,5 + log₁₀ [0,04] / [0,06]

<em>pH = 9,32</em>

<em></em>

I hope it helps!

4 0
3 years ago
How many moles of water are in 1.23 x 10 to the 18th power water molecules
mamaluj [8]

Divide the number of molecules you have by, 6.022 x 10^23. This will give you the moles of water, or the moles of anything, since there is always 6.022 x 10^23 molecules in 1 mole of substance. 

1.23x10^24 atoms/6.022x10^23 atom/mole = 2.04 mole H20 



3 0
3 years ago
Read 2 more answers
5. A group decided to use 250.0 mL of vinegar and 24.0 grams of baking soda. What is the limiting
Korolek [52]

Hence,  If the concentration of Acetic acid in vinegar is more than 7%, the limiting reactant is baking soda. If the concentration of Acetic acid in vinegar is less than 7%, the limiting reactant is vinegar.

<h3>What is a limiting reactant?</h3>

The limiting reactant (or limiting reagent) is the reactant that gets consumed first in a chemical reaction and therefore limits how much product can be formed.

To solve this problem, it is necessary to know the exact concentration of acetic acid in vinegar, because manufacturers produce many types of vinegar the with different concentrations. Most often, concentration of acetic acid in vinegar ranges from 4% to 8%. In this case, it is possible

to calculate the concentration of vinegar making the assumption that 250 ml of vinegar reacts completely with 24 grams of baking soda.

Acetic acid CH_3CO_2H  reacts with baking soda NaHCO_3 according to the equation:

CH_3CO_2H  + NaHCO_3 → CH_3CO_2Na + CO_2 + H_2O

1. Molar mass of NaHCO_3 is 23+1+12+16×3 = 84 g/mol

= \frac{1 mol \;NaHCO_3}{84 g \;NaHCO_3}

= \frac{24 g \;NaHCO_3 X 1 mol \;NaHCO_3}{84 g \;NaHCO_3}

=0.29 mol NaHCO_3

2. From the balanced equation we see that 1 mole of NaHCO_3 reacts with 1 mole of CH_3CO_2H , then 0.29 moles of NaHCO_3 react with 0.29 moles of CH_3CO_2H.

3. Mass of 1 mole of CH_3CO_2H is 12+ 1×3+12+16×2=60 g/mol

= \frac{0.29 mol \;CH_3CO_2H X \;60 g \;CH_3CO_2H }{1 mol \;CH_3CO_2H}

=17.4 g CH_3CO_2H

4. In this step density of vinegar is needed.

Making the assumption that concentration of acetic acid is 7%, we can calculate the mass of acetic acid in 250 ml of vinegar:

Mass of vinegar=Volume × density

= 250 ml ×1.0084 g/ml

=252 g

Mass of acetic acid = mass of vinegar × concentration ÷ 100%

= 252 g × 7% ÷ 100%

= 17.6 g.

17.6 g CH_3CO_2H is very close to 17.4 g CH_3CO_2H. It means, that 250 ml of vinegar with a concentration of acetic acid equal to 7% reacts completely with 24 g of baking soda.

Hence,  If the concentration of Acetic acid in vinegar is more than 7%, the limiting reactant is baking soda. If the concentration of Acetic acid in vinegar is less than 7%, the limiting reactant is vinegar.

Learn more about the limiting reactant here:

brainly.com/question/19654705

#SPJ1

4 0
2 years ago
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