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creativ13 [48]
3 years ago
7

Explain the “war of the currents” please help with at least 1 sentence

Chemistry
1 answer:
Alex777 [14]3 years ago
3 0

Answer:

The war of the currents, sometimes called battle of the currents, was a series of events surrounding the introduction of competing electric power transmission systems in the late 1880s and early 1890s.

Explanation:

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What quality of a drop of water increases as it gets closer to the earth surface I’m thinking it’s velocity but I don’t know
AnnyKZ [126]

Answer: the correct answer is C velocity.

Explanation: I just got the answer wrong on the exam.

8 0
2 years ago
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Be sure to answer all parts.
MrRissso [65]

Answer: The molarity of each of the given solutions is:

(a) 1.38 M

(b) 0.94 M

(c) 1.182 M

Explanation:

Molarity is the number of moles of a substance present in liter of a solution.

And, moles is the mass of a substance divided by its molar mass.

(a) Moles of ethanol (molar mass = 46 g/mol) is as follows.

Moles = \frac{mass}{molar mass}\\= \frac{28.5 g}{46 g/mol}\\= 0.619 mol

Now, molarity of ethanol solution is as follows.

Molarity = \frac{moles}{Volume (in L)}\\= \frac{0.619 mol}{4.50 \times 10^{2} \times 10^{-3}L}\\= 1.38 M

(b) Moles of sucrose (molar mass = 342.3 g/mol) is as follows.

Moles = \frac{mass}{molar mass}\\= \frac{21.6 g}{342.3 g/mol}\\= 0.063 mol

Now, molarity of sucrose solution is as follows.

Molarity = \frac{moles}{Volume (in L)}\\= \frac{0.063 mol}{0.067 L}  (1 mL = 0.001 L)\\= 0.94 M

(c) Moles of sodium chloride (molar mass = 58.44 g/mol) are as follows.

Moles = \frac{mass}{molar mass}\\= \frac{6.65 g}{58.44 g/mol}\\= 0.114 mol

Now, molarity of sodium chloride solution is as follows.

Molarity = \frac{moles}{Volume (in L)}\\= \frac{0.114 mol}{0.0962 L}\\= 1.182 M

Thus, we can conclude that the molarity of each of the given solutions is:

(a) 1.38 M

(b) 0.94 M

(c) 1.182 M

4 0
3 years ago
Lab reaction rate project for chemistry edge2020
guajiro [1.7K]

Answer:

What Affects Reaction Rate?

The purpose of this lab was to see how temperature and particle size affects reaction rate. The first hypothesis is if you increase the temperature of a reaction, then the reaction rate will increase because particles experience more collisions at higher temperatures.The second hypothesis is if you decrease the particle size of a reactant, then the reaction rate will increase because more of the reactants’ molecules will contact each other. The independent variables are particle size and temperature. The dependent variable is reaction rate.

Materials

250 mL graduated cylinder

Thermometer

Water

Timer

Four 250 mL beakers

Seven 1,000 mg effervescent tablets

Two pieces of filter paper

600 mL beaker

Ice

Hot plate

Procedure

Step 1:Gather Materials

Variation of Temperature

Step 2:Measure the Reaction Rate at ≈ 20°C (Room Temperature)

a) Using a graduated cylinder, fill a 250 mL beaker with 200 mL of water.

b) Measure the temperature of the water and record it in the correct row of Table A.

c) Reset the timer. Start the timer as you place a full tablet into the beaker.

d) Record the reaction time on the Data Sheet in the correct row of Table A.

e) Compute the reaction rate to the nearest mg/L/sec. Record it in the last column of Table A. Measure the Reaction Rate at ≈ 40°C

Step 3:Repeat Step 2, heating the water to approximately 40°C using a hot plate during sub-step a. Measure the Reaction Rate at ≈ 65°C

Step 4:Repeat Step 2, heating the water to approximately 65°C using a hot plate during sub-step a. Measure the Reaction Rate at ≈ 5°C

Step 5:Repeat Step 2, chilling the water to approximately 5°C inside an ice bath during sub-step a. (To create an ice bath, place 100 mL of ice and 100 mL of water in a 600 mL beaker of ice water and wait until the temperature reaches approximately 5°C. To save time, you may wish to set up the ice bath, using an additional 250 mL beaker, while working on Step 4.)

Variation of Particle Size

Step 6:Measure the Reaction Rate for a Full Tablet

a) Using a graduated cylinder, fill a 250 mL beaker with 200 mL of water.

b) Reset the timer. Start the timer as you place the tablet in the beaker.

c) Record the reaction time on the Data Sheet in the appropriate row of Table B.

d) Compute the reaction rate to the nearest mg/L/sec. Record it in the last column of Table B.

Step 7:Measure the Reaction Rate for a Partially Broken Tablet

Repeat Step 6, but this time break the tablet into eight small pieces on a piece of filter paper. Make sure to place all of the pieces into the beaker at the same time.

Step 8:Measure the Reaction Rate for a Crushed Tablet

Repeat Step 6, but this time crush the tablet into tiny pieces on a piece of filter paper. Make sure to place all of the pieces into the beaker at the same time.

Step 9: Dispose of all samples according to your teacher’s directions.

Measured Reaction Temperature (°C)

Mass of Tablet (mg)

Volume of Water (L)

Reaction Time (s)

Reaction Rate (mg/L/s)

≈20°C

24

1,000

0.2

34.2

146.2

≈40°C

40

1,000

0.2

26.3

190.1

≈65°C

65

1,000

0.2

14.2

352.1

≈5°C

3

1,000

0.2

138.5

36.1

Relative Particle Size (Small, Medium, Large)

Mass of Tablet (mg)

Volume of Water (L)

Reaction Time (s)

Reaction Rate (mg/L/s)

Full Tablet

large

1,000

0.2

34.5

144.9

Broken Tablet

medium

1,000

0.2

28.9

173.0

Crushed Tablet

small

1,000

0.2

23.1

216.5

The data in the first table show that as the temperature increases the reaction time decreases and in turn the reaction rate increases. The data supported the hypothesis that as temperature increases reaction rate will also increase. The second table shows that as the particle size decreases the reaction time increases because there is more surface area when the particles are smaller. The data in the second table supported the second hypothesis that as particle size decreases the reaction rate will increase because there will be more contact in the molecules. Possible source of error would be an error in stopping the timer in time or chips in the tablets. To improve this lab it could be done with different types of reactions or different temperature or different particle sizes.

Explanation:

6 0
2 years ago
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Anthracene is a yellow, crystalline solid found in coal tar. complete this structure for anthracene, c14h10, by adding bonds and
Assoli18 [71]

Anthracene is a polycyclic aromatic hydrocarbon with chemical formula C₁₄H₁₀. The number of fused rings in Anthracene are three in number. This compound is colorful and is used in the formation of different dyes due to its property of deloclization of pi electrons. All the carbon atoms in Anthracene are sp² hybridized with a trigonal planar structure hence, the Anthracene is planar in nature.

Number of Sigma Bonds:

                                         There are 26 sigma bonds (colored in Blue) in Anthracene among which 10 sigma bonds are between carbon and hydrogen atoms while the remaining are between the carbon atoms.

Number of Pi-Bonds:

                                  There are 7 pi bonds in Anthracene (colored in red). All pi bonds are present between carbon and carbon atoms.

Number of Electrons in Sigma Bonds:

                                                             As one sigma bond is formed by 2 electrons hence, 26 sigma bonds will be formed by 52 electrons.

Number of Electrons in Pi Bonds:

                                                       As one pi bond is formed by the side wise overlap of two p orbitals hence one pi bond is formed by two electrons so, 7 pi bonds will be formed by 14 electrons.

7 0
3 years ago
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What is a modern example of the scientific revolution
blsea [12.9K]

Answer:

Perhaps the best example of such a paradigm shift in science is the Copernican revolution in cosmology: the move from a geocentric to the heliocentric view of our solar system.

Explanation:

7 0
3 years ago
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