What is the pOH of a solution of HNO, that has (OH 1=9,50 * 10M2

The total number of electrons in the outer shell of a sodium atom is?<br>A. 1<br>B.2<br>C.8<br>D.18

mrs_skeptik [129]

Answer:

1

Explanation:

outershell atoms of an element are also known as valency of that element

so the valency and number of elctron in the outershell of a sodium atom is +1.

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7 0

3 years ago

Any one know the answer?

quester [9]

The last one, answer is D

8 0

4 years ago

Which of these limiting factors is MOST likely to affect low-growing plants in a tropical forest? Group of answer choices air wa

Georgia [21]

Answer:

air, water, sunlight

Explanation:

A limiting factor may be defined as a environmental condition or a resource that can limit the plant growth as well as distribution or the abundance of an organism or its population within the ecosystem. The ability of any plant species to grow and spread throughout any geographic area is the direct result of the adaption to its biotic and abiotic components of that region.

Some of the factor that affect the plant growth are : sunlight, air, proper temperature, moisture, nutrients, wind,etc.

The lack of the any one of the above essential component will determine the health of the plant.

8 0

4 years ago

Which of the following is an

eimsori [14]

Answer:

2 and 4

Explanation:

The rest of the changes are chemical. 1 has a chemical reaction happen which makes light sticks glow. 3 is because browning the meat actually causes some new compounds to form and cause caramelization.

For 2, the oxygen is simply heating up and expanding which pops the balloon. 4 is just a phase change of water vapor to liquid water.

5 0

3 years ago

Write the oxidation and reduction half reactions;

luda_lava [24]

Answer:

a)

$Fe^{2+}$ ⇒ $Fe^{3+}+e^-$

$Br_2+2e^-$ ⇒ $2Br^-$

b)

$Mg$ ⇒ $Mg^{2+}+2e^-$

$Cr^{3+}+e^-$ ⇒ $Cr^{3+}$

Explanation:

A)

Remember that positive number superscripts mean electrons lack and negative numbers mean electrons 'excess' (if we compare it with the neutral element). So, for the case of Fe2+ which is converted to Fe3+, we know that in Fe2+ there is a two electrons lack, while in Fe3+ there is a 3 electrons lack; it means that Fe2+ was converted to Fe3+ but releasing one electron:

$Fe^{2+}$ ⇒ $Fe^{3+}+e^-$

The same analysis is applied to Br2; Br2 is a molecule which is said to have a zero superscript because it is an apolar covalent bond; and it is converted to Br-, which, according to what I wrote above, means that there is a one electron excess. So, Br2 must have received an electron in order to change to Br-; but Br2 can't change to Br- as simple as that because Br2 is a molecule, not an atom; it is a molecule that has two Br atoms, so, Br2 must give two Br- ions as products, but receiving one electron for each one:

$Br_2+2e^-$ ⇒ $2Br^-$

b)

Applying the same, in Mg2+ there is a 2 electrons lack, and in Mg is not electron lack (its superscript is zero), so Mg must have released two electrons in order to change to Mg2+:

$Mg$ ⇒ $Mg^{2+}+2e^-$

Cr3+ has a 3 electrons lack, and Cr2+ a two electrons one, so, Cr3+ must receive an electron to convert to Cr2+:

$Cr^{3+}+e^-$ ⇒ $Cr^{3+}$

3 0

4 years ago

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