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scoray [572]
3 years ago
10

15 POINTS. What is the area of the circle segment/shaded area? Picture included please help. Please answer in a way that will fi

ll in the blanks, explanation preferred.

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
8 0
I hope this helps you

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To estimate the average salary among people in a certain district, a marketing team obtains a simple random sample of 100 people
bogdanovich [222]

Answer:

The interpretation is that we are 90% sure that the true average salary of the district is in this interval.

Step-by-step explanation:

x% confidence interval:

A confidence interval is built from a sample, has bounds a and b, and has a confidence level of x%. It means that we are x% confident that the population mean is between a and b.

In this question:

The 90% confidence interval for the average salary of the district is  [41500,49750].

This means that we are 90% sure that the true average salary of the district is in this interval.

3 0
3 years ago
Please help I dont understand​
Kitty [74]

Answer:

3rd option

Step-by-step explanation:

A direct variation is expressed in this form:

y = kx

1. y - 4x = 8

y = 4x + 8 is not a direct variation

2. y + 2 = 7x

y = 7x - 2 is not a direct variation

3. y - 3x = 0

y = 3x is a direct variation

4. y = 5x - 2

y = 5x - 2 is not direct variation

8 0
2 years ago
If P(AnB)=2/3 and P(B)=3/4, what is P(A I B)? A.35/36 B.15/16 C.24/25 D.8/9
astraxan [27]

Answer:

\large\boxed{D.\ \dfrac{8}{9}}

Step-by-step explanation:

\text{We know:}\\\\P(A|B)=\dfrac{P(A\ \cap\ B)}{P(B)}\\\\\text{We have:}\\\\P(A\ \cap\ B)=\dfrac{2}{3},\ P(B)=\dfrac{3}{4}.\\\\\text{Substitute:}\\\\P(A|B)=\dfrac{\frac{2}{3}}{\frac{3}{4}}=\dfrac{2}{3}:\dfrac{3}{4}=\dfrac{2}{3}\cdot\dfrac{4}{3}=\dfrac{8}{9}

6 0
3 years ago
Solve the initial value problem. dy/dt = 1 + 6/t , t > 0, y = 8 when t = 1
nordsb [41]
\displaystyle\frac{dy}{dt} = 1 + \frac{6}{t}\ \Rightarrow\ dy = \left( 1 + \frac{6}{t}\right) dt\ \Rightarrow\int 1\, dy = \int \left( 1 + \frac{6}{t}\right) dt \ \Rightarrow \\ \\
y = t + 6\ln|t| + C. \text{ But $t\ \textgreater \ 0$ so }y = t + 6\ln t + C. \\ \\ 
y(1) = 8\ \Rightarrow\ 8 = 1 + 6 \ln 1 + C \ \Rightarrow\ C = 7 \text{ so } \\ \\
y(t) = t + 6\ln t + 7
5 0
3 years ago
The gas mileage for a certain vehicle can be approximated by m=−0.05x2+3.5x−49, where x is the speed of the vehicle in mph. Dete
Whitepunk [10]

Answer:

<h2>14mph</h2>

Step-by-step explanation:

Given the gas mileage for a certain vehicle modeled by the equation m=−0.05x²+3.5x−49 where x is the speed of the vehicle in mph. In order to determine the speed(s) at which the car gets 9 mpg, we will substitute the value of m = 9 into the modeled equation and calculate x as shown;

m = −0.05x²+3.5x−49

when m= 9

9 = −0.05x²+3.5x−49

−0.05x²+3.5x−49 = 9

0.05x²-3.5x+49 = -9

Multiplying through by 100

5x²+350x−4900 = 900

Dividing through by 5;

x²+70x−980 = 180

x²+70x−980 - 180 = 0

x²+70x−1160 = 0

Using the general formula to get x;

a = 1, b = 70, c = -1160

x = -70±√70²-4(1)(-1160)/2

x = -70±√4900+4640)/2

x = -70±(√4900+4640)/2

x = -70±√9540/2

x =  -70±97.7/2

x = -70+97.7/2

x = 27.7/2

x = 13.85mph

x ≈ 14 mph

Hence, the speed(s) at which the car gets 9 mpg to the nearest mph is 14mph

4 0
2 years ago
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