1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Agata [3.3K]
2 years ago
13

Write 2/5 + 1/3 answer as a fraction. Show your work.

Mathematics
1 answer:
Diano4ka-milaya [45]2 years ago
8 0

Answer: 11/15

Step-by-step explanation:2

5

+

1

3

=

2 × 3

5 × 3

+

1 × 5

3 × 5

=

6

15

+

5

15

=

6 + 5

15

=

11

15

You might be interested in
In the past decades there have been intensive antismoking campaigns sponsored by both federal and private agencies. In one study
DIA [1.3K]

Answer:

z=\frac{0.384-0.362}{\sqrt{0.374(1-0.374)(\frac{1}{4276}+\frac{1}{3908})}}=2.055    

The p value can be calculated from the alternative hypothesis with this probability:

p_v =2*P(Z>2.055)=0.0399    

And the best option for this case would be:

C. between 0.01 and 0.05.

Step-by-step explanation:

Information provided

X_{1}=1642 represent the number of smokers from the sample in 1995

X_{2}=1415 represent the number of smokers from the sample in 2010

n_{1}=4276 sample from 1995

n_{2}=3908 sample from 2010  

p_{1}=\frac{1642}{4276}=0.384 represent the proportion of smokers from the sample in 1995

p_{2}=\frac{1415}{3908}=0.362 represent the proportion of smokers from the sample in 2010

\hat p represent the pooled estimate of p

z would represent the statistic    

p_v represent the value for the pvalue

System of hypothesis

We want to test the equality of the proportion of smokers and the system of hypothesis are:    

Null hypothesis:p_{1} = p_{2}    

Alternative hypothesis:p_{1} \neq p_{2}    

The statistic is given by:

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{1642+1415}{4276+3908}=0.374  

Replacing the info given we got:

z=\frac{0.384-0.362}{\sqrt{0.374(1-0.374)(\frac{1}{4276}+\frac{1}{3908})}}=2.055    

The p value can be calculated from the alternative hypothesis with this probability:

p_v =2*P(Z>2.055)=0.0399    

And the best option for this case would be:

C. between 0.01 and 0.05.

7 0
3 years ago
Please help with Math questions!
m_a_m_a [10]
1) 4, because 4/5 is closer to 4 than it is 3 1/2. 

2) 100

3) 5

3 0
3 years ago
What can be concluded from the statement ∠1 + ∠2 = 90°?
irinina [24]
  • <1+<2=90°

The sum of measures of angles A and B is 90°

Hence the angles are complementary

  • As complementary angles have sum 90°

8 0
2 years ago
Alex has 905 stickers. some of them are animal stickers and the rest of them are airplanes stickers. how many of each could he h
Nookie1986 [14]
You could solve this by doing 905 divided by the total of animal stickers
6 0
3 years ago
Can someone please help me!!! I need help, no links !!!
Sholpan [36]
Give me a few and I will
4 0
3 years ago
Other questions:
  • How do you solve each system by elimination
    5·1 answer
  • For all real numbers a and b, 2a • b = a2 + b2<br><br> True Or False ! Explain
    5·2 answers
  • 0.561 rounded to the nearest hundredth is what
    15·2 answers
  • How many pints in a quart
    12·2 answers
  • Write this number in scientific notation 38200000 <br> Look at attachment down below
    15·2 answers
  • Select all the properties of a right triangle.
    12·2 answers
  • PLEASE HELP! I've reposted this soooo many times and no one answered, I WILL GIVE BRAINLIEST!​
    6·2 answers
  • Use the inequality sign to show which situation has the greater unit rate.
    9·1 answer
  • Four red, 8 blue, and 5 green balls are randomly arranged in a line. (a) What is the probability that the first 5 balls are blue
    6·1 answer
  • A solid metal sphere of radius 9 is melted and transformed into 3 identical spheres. What is the ratio of the surface area of on
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!