The number of miles in day at which the rental cost for the company A and Company B are the same is 200 miles
The Company A rented the truck for $40 a day plus $0.40 per miles
The expression will be
40+0.40x
Where x is the number of miles
The company B rented the truck for $20 a day plus $0.50 per miles
20+0.50x
To find the number of miles in a day at which the rental costs for Company A and Company B are the same, the linear equation will be
40+0.40x = 20+0.50x
40-20 = 0.50x-0.40x
0.1x = 20
x = 200 miles
Hence, the number of miles in day at which the rental cost for the company A and Company B are the same is 200 miles
Learn more about linear equation here
brainly.com/question/13738061
#SPJ1
Amount of Interest (I) = P * R * T /100
I = 1675 * 4.6 * 4 /100
I = 308.20
Balance = Initial amount + Interest amount
B = 1675 + 308.20 = 1983.20
In short, Your Answer would be $1983.20
Hope this helps!
I think it’s four. If not then I’m sorry
multiply the amount of one piece with the number of pieces
1.85×8=14.8
x = -1
y = 1
To find this, input the equation into a graphing calculator, whether online or an actual one, and you have two options:
1 - Search for the points in which the line crosses the x and or y axis.
2 - Hit 2nd Graph to access the table and find when x and y equal zero.
Hope this helps!
