Question

The industrial process that is used to convert a fuel to gasoline is carried out at a temperature range of 660 degrees°F to 790 degrees°F. Using F as the​ variable, write an absolute value inequality that corresponds to this range.

Answer 1

Answer:

$|F-725|$

With F represent the variable of interest:

$-65< F-725< 65$

$-65+725< F< 65+725$

$660 < F< 790$

Step-by-step explanation:

For this case we have a normal limits for the temperature Range. The minimum is 660 F and the maximum 790 F.

We can find the midpoint of this interval like this:

$Midpoint= \frac{660+790}{2}= 725$

And the difference between the midpoint and the limits are:

$|790-725|= 65$

$|680-725|= 65$

So then we can create the following inequality:

$|F-725|$

With F represent the variable of interest.:

$-65< F-725< 65$

$-65+725< F< 65+725$

$660 < F< 790$