1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
svet-max [94.6K]
3 years ago
10

Please help!!!!!!!!!

Mathematics
1 answer:
sveticcg [70]3 years ago
4 0
A) y=kx

2 = 16k
2/16 = k
0.125 = k
Y = 0.125x

B) y= 0.125x

Y= 0.125(7)
Y= 0.875

Hope this helps
You might be interested in
Please help i’ll mark brainlist
jeyben [28]

Answer:I think the answer is multiplication property of equality

Step-by-step explanation:

it is being multiplied to get the answer so that should be the answer

8 0
2 years ago
Read 2 more answers
You select a marble without looking and then put it back. If you do this 5 times, what is the best prediction possible for the n
Rama09 [41]

Answer:

You have a chance to get the pink marble at least once.

7 0
2 years ago
Read 2 more answers
A college infirmary conducted an experiment to determine the degree of relief provided by three cough remedies. Each cough remed
KiRa [710]

Answer:

p_v = P(\chi^2_{4,0.05} >3.81)=0.43233

Since the p values is higher than the significance level we FAIL to reject the null hypothesis at 5% of significance, and we can conclude that we don't have significant differences between the 3 remedies analyzed. So we can say that the 3 remedies ar approximately equally effective.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

                               NyQuil          Robitussin       Triaminic     Total

No relief                    11                     13                      9               33

Some relief               32                   28                     27              87

Total relief                7                       9                      14               30

Total                         50                    50                    50              150

We need to conduct a chi square test in order to check the following hypothesis:

H0: There is no difference in the three remedies

H1: There is a difference in the three remedies

The level os significance assumed for this case is \alpha=0.05

The statistic to check the hypothesis is given by:

\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

The table given represent the observed values, we just need to calculate the expected values with the following formula E_i = \frac{total col * total row}{grand total}

And the calculations are given by:

E_{1} =\frac{50*33}{150}=11

E_{2} =\frac{50*33}{150}=11

E_{3} =\frac{50*33}{150}=11

E_{4} =\frac{50*87}{150}=29

E_{5} =\frac{50*87}{150}=29

E_{6} =\frac{50*87}{150}=29

E_{7} =\frac{50*30}{150}=10

E_{8} =\frac{50*30}{150}=10

E_{9} =\frac{50*30}{150}=10

And the expected values are given by:

                               NyQuil          Robitussin       Triaminic     Total

No relief                    11                     11                       11               33

Some relief               29                   29                     29              87

Total relief                10                     10                     10               30

Total                         50                    50                    50              150

And now we can calculate the statistic:

\chi^2 = \frac{(11-11)^2}{11}+\frac{(13-11)^2}{11}+\frac{(9-11)^2}{11}+\frac{(32-29)^2}{29}+\frac{(28-29)^2}{29}+\frac{(27-29)^2}{29}+\frac{(7-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(14-10)^2}{10} =3.81

Now we can calculate the degrees of freedom for the statistic given by:

df=(rows-1)(cols-1)=(3-1)(3-1)=4

And we can calculate the p value given by:

p_v = P(\chi^2_{4,0.05} >3.81)=0.43233

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(3.81,4,TRUE)"

Since the p values is higher than the significance level we FAIL to reject the null hypothesis at 5% of significance, and we can conclude that we don't have significant differences between the 3 remedies analyzed.

4 0
3 years ago
If the first term is 5 and the common difference is -3?
Doss [256]
-2 is the answer
----------------------------
You're Welcome.


6 0
3 years ago
You roll two dice. What is the probability you get a 2 and a number greater than 2?
abruzzese [7]
Hello!

You have to find the probability of getting a 2

This is a 1/6 chance

Then you have to find the chance of getting a number greater than 2

This is a 4/6 chance

To find the chance of these happening at the same time you multiply these together

1/6 * 4/6 = 1/9

There is a 1/9 chance

Hope this helps!
6 0
3 years ago
Read 2 more answers
Other questions:
  • F(x)= 2x^2 + k/x point of inflection at x=-1 then value of k is
    15·1 answer
  • Ugh help please i need assistance no one will help me.
    15·2 answers
  • The modulus of a real number, n, is equal to _____.
    6·1 answer
  • Which graph below shows the equations y=|x| and y=3|x| for the interval -3< x <3?
    10·2 answers
  • The ratio of sixth-grade students to fifth-grade students in the Kirkpatrick Elementary school band is 5:4. If there are 20 fift
    8·1 answer
  • What is 389*1094 need help
    7·1 answer
  • Math please help <br> This is my last work of the year
    12·2 answers
  • 30 points available will give brainliest plz helpp need soon<br>i need it quick
    14·1 answer
  • Mrs. Peña is taking a group of 50 students on a field trip to the Georgia Aquarium. If 20 of the students are boys, what percent
    10·1 answer
  • Please look for the question in the picture.
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!