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Ahat [919]
4 years ago
14

What is the greatest positive three-digit integer that is divisible by 5, 7 and 9?

Mathematics
2 answers:
zhenek [66]4 years ago
7 0

<u>Find LCM:</u>

5 = 5

7 = 7

9 = 3²

LCM = 3² x 5 x 7 = 315

-

<u>Greatest 3-digit number:</u>

Greatest 3-digit number = 999

-

<u>Find greatest 3-digit number divisible by 315:</u>

999 ÷ 315 = 3 remainder 54

Greatest 3-digit number divisible by 315 = 315 x 3 =<u> 945.</u>

-

Answer: 945

Verdich [7]4 years ago
6 0

First, we want to see what the product of the three numbers is:

9 * 7 * 5 = 315

From there, we can find multiples of 315 to get the largest 3- digit number divisible by 9, 7, and 5.

315, 630, 945, 1260...

The largest is 945.

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Find the distance from the point (1, 4) to the line y = 1/3x – 3. A) 2(square root) 10 units B) 4 units C) 4(square root) 2 unit
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4 years ago
Nevermind. I dont need anything
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