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liraira [26]
3 years ago
13

Px + qy = r 2px - qy = 2r When solving this system of equations, x =

Mathematics
2 answers:
VladimirAG [237]3 years ago
8 0
Px + qy = r
2px - qy = 2r
----------------add
3px = 3r

x = 3r/3p
x = r/p
expeople1 [14]3 years ago
8 0
You just add the equations:
  px + qy = r
2px  - qy = 2r
3px = 3r
divide by 3
px = r
divide by p
x = (r)/(p)
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A = \frac{P(\frac{r}{12} )}{(1 -(1 +r/12)^{(-12t)}}

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Keenan scored 80 points on an exam that had a mean score of 77 points and a standard deviation of 4.9 points. Rachel scored 78 p
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Answer:

Keenan's z-score was of 0.61.

Rachel's z-score was of 0.81.

Step-by-step explanation:

Z-score:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Keenan scored 80 points on an exam that had a mean score of 77 points and a standard deviation of 4.9 points.

This means that X = 80, \mu = 77, \sigma = 4.9

So

Z = \frac{X - \mu}{\sigma}

Z = \frac{80 - 77}{4.9}

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Keenan's z-score was of 0.61.

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This means that X = 78, \mu = 75, \sigma = 3.7. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{75 - 78}{3.7}

Z = 0.81

Rachel's z-score was of 0.81.

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2 years ago
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