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3 years ago

5

Of regular movie goers, 40% watch romantic movies, 60% watch action movies, and 24% watch both types. Are watching romantic movi

es independent or dependent of watching action movies?

1 answer:

Scilla [17]3 years ago

8 0

Answer:

depend on watching action movies

Step-by-step explanation:

because most watch action

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You are making a poster to support your friend for homecoming. Your original photo is 4 inches by 6 inches. You want the photo o

Maru [420]

Scale factor is 1 to 6

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3 years ago

6(4r + 2b = 24r + 12b =<br><br><br>If possible could I please have an explanation?

almond37 [142]

Step-by-step explanation:

24r+2b=24r+2b

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4 0

3 years ago

Please Elijah and Aubrey have summer jobs Elijah deposits the same amount of money in his account every week the equation is y =

Anika [276]

Answer:

Part a) $y=125x+23$

Part b) The graph of the equation for Aubrey's balance is parallel to the graph of Elijah's balance

Part c) Parallel graphs mean that their slopes are the same and that they deposited the same amount of $125 per week into their account balance during the summer.

Step-by-step explanation:

<u><em>The correct question is</em></u>

Elijah and Aubrey have summer jobs. Elijah deposits the same

amount of money in his account every week. The equation y = 125x + 72 represents his bank balance any given week of the summer. Aubrey also deposits the same amount into her account every week. At the end of the third week she has $398. At the end of the sixth week she has $773.

a. Write an equation to represent Aubrey's bank balance any given week of the summer.

b. Would the graph of the equation for Aubrey's balance be parallel to the graph of Elijah's balance? Explain.

c. What do the parallel graphs mean in terms of the situation?

Part a)

Let

x ----> the number of weeks

y ----> represent bank's balance

we know that

<em>Elijah</em>

$y=125x+72$ -----> equation A

<em>Aubrey</em>

we have the points

(3,398) and (6,773)

Find the slope m

$m=(773-398)/(6-3)$

$m=375/3$

$m=125$

Find the equation of the line in point slope form

$y-y1=m(x-x1)$

we have

$m=125$

$point\ (3,398)$

substitute

$y-398=125(x-3)$ ----> equation in point slope form

Convert to slope intercept form

$y=mx+b$

$y-398=125x-375$

$y=125x-375+398$

$y=125x+23$ ----> Aubrey's bank balance

Part b)

Compare the equations

$y=125x+72$ ----> Elija's bank balance

$y=125x+23$ ----> Aubrey's bank balance

Remember that

If two lines are parallel, then their slopes are equal

In this problem the slopes are equal

$m=125\frac{\$}{week}$

therefore

The graph of the equation for Aubrey's balance is parallel to the graph of Elijah's balance

Part c) Parallel graphs mean that their slopes are the same and that they deposited the same amount of $125 per week into their account balance during the summer.

5 0

3 years ago

5. SHORT ANSWER A pair of jeans that normally sells for $35 is on sale for 20% off Find the sale price of the jeans. Then find t

Grace [21]

First, find the amount the sale is worth. To do such a thing, calculate 20% of 35$ like this
(35 * 20) / 100 = ?

To find the cost of 1 jean, take the sale's worth off the full price.
35 - ? = $

Then, multiply it by 6, for 6 jeans.
$ * 6 =

6 0

3 years ago

Read 2 more answers

Victoria is interested in opening her own candy store. She has researched and found that of the 14 stores she investigated, the

Anna71 [15]

Answer:

99% confidence interval for the average start up cost is [76.575 , 123.425].

Step-by-step explanation:

We are given that of the 14 stores Victoria investigated, the average start up cost is 100 thousand dollars with a standard deviation of 29.1 thousand dollars.

So, the pivotal quantity for 99% confidence interval for the population average start up cost is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample average start up cost = 100 thousand dollars

$\sigma$ = sample standard deviation = 29.1 thousand dollars

n = sample of stores = 14

$\mu$ = population average start up cost

<em>So, 99% confidence interval for the average start up cost, </em> $\mu$ <em> is ;</em>

P(-3.012 < $t_1_3$ < 3.012) = 0.99

P(-3.012 < $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ < 3.012) = 0.99

P( $-3.012 \times {\frac{s}{\sqrt{n} }$ < ${\bar X - \mu}$ < $3.012 \times {\frac{s}{\sqrt{n} }$ ) = 0.99

P( $\bar X-3.012 \times {\frac{s}{\sqrt{n} }$ < $\mu$ < $\bar X +3.012 \times {\frac{s}{\sqrt{n} }$ ) = 0.99

<u>99% confidence interval for</u> $\mu$ = [ $\bar X-3.012 \times {\frac{s}{\sqrt{n} }$ , $\bar X +3.012 \times {\frac{s}{\sqrt{n} }$ ]

= [ $100-3.012 \times {\frac{29.1}{\sqrt{14} }$ , $100+3.012 \times {\frac{29.1}{\sqrt{14} }$ ]

= [76.575 , 123.425]

Therefore, 99% confidence interval for the population average start up cost for a candy store is [76.575 , 123.425].

8 0

3 years ago