His mistake was adding 12+2 when he was supposed to subtract.
Let the three consecutive equals:
x, x+1, x+2
sum:
x+(x+1)+(x+2) = 36
3x + 3 = 36
x+1 = 36/3
x+1 = 12
x=12-1
x=11
The total number of possible combinations from flipping a coin 10 times is 2^10 = 1024.
Answer:
Jana had 8 oranges, and Jordan had 15 oranges.
Step-by-step explanation:
First, identify what you know:
1) In total, Jana and Jordan had 23 oranges.
2) Jana had 7 less oranges than Jordan.
We can create a formula, where x equals the number of oranges Jana has.
23 = x + (x + 7)
16 = x + x (subtracted 7 from both sides)
x = 8 (divided both sides by 2)
So, now we know Jana had 8 oranges, which is 7 less than Jordan.
8 + 7 = ?
? = 15
Jana had 8 oranges, while Jordan had 15, for a total of 23 oranges.
