Answer:
At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.
Step-by-step explanation:
Hello!
Considering the dependent variable:
Y: Ductility in steel.
And the independent variable:
X: Carbon content of the steel.
The linear regression was estimated and a prediction interval was calculated.
The prediction interval is calculated to predict a value that the variable Y (response variable) can take for a given value of the variable X (predictor variable) in the definition range of the linear regression line. Symbolically [Y/X=
]
In this case 95% prediction interval for Y/X=0.5
At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.
I hope it helps!
The x coordinate of S will be 1/2 * 2a = a.
and since the half triangle is 30-60-90 the y coordinate will be sqrt3 a
so S is (a , sqrt3a)
Answer: 122 sq. in.
Step-by-step explanation:
P = 2 (l + w)
P = 2 (34.5 + 26.5)
P = 2 x 61
P = 122 sq. in. = 0.847 sq ft = 0.0941 sq. yards
Here is your answer. Good luck!
Answer:
2/3 liter
Step-by-step explanation:
3.00 g/cm³ = 3.00 kg/L . . . . . . . 1000 g = 1 kg; 1000 cm³ = 1 L
For a mass of 2.00 kg, you need ...
(2.00 kg)/(3.00 kg/L) = 2/3 L ≈ 0.667 L