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Lilit [14]
2 years ago
12

Deshawn is serving ice cream with the birthday cake at his party.He has purchased 19 1/2 pints of ice cream. He will serve 3/4 o

f a pint to each guest.
a.How many guests can be served ice cream?

b.Will there be any ice cream left?Justify your answer.
Mathematics
1 answer:
soldier1979 [14.2K]2 years ago
8 0
26 and no there will not be any left
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The number of 90° angles formed by the intersections of and the two parallel lines and is
Ber [7]

Answer:

is there supposed to be a picture that goes with this

Step-by-step explanation:

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3 0
3 years ago
ANSWER THIS STAT PLEASE &amp; THANKS<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B5%7D%7B7%7D%20%20%5C%3A%20%20-%20%20%5Cfr
Brut [27]

\frac{27}{24} or 1 \frac{1}{8} is the answer

7 0
3 years ago
Find the y intercept of the straight line with the following equations y=7+3x <br><br>3y=6x+12
neonofarm [45]

y = 7 + 3x

y = 3x + 7

y = mx + b, therefore the y-intercept is 7.


3y =  6x + 12

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y = mx + b, therefore the y-intercept is 4.

8 0
3 years ago
Regarding the violation of multicollinearity, which of the following description is wrong?
MA_775_DIABLO [31]

Complete question is;

Regarding the violation of multicollinearity, which of the following description is wrong?

a. It changes the intercept of the regression line.

b. It changes the sign of the slope.

c. It changes the slope of the regression line.

d. It changes the value of F-tests.

e. It changes the value of T-tests

Answer:

a. It changes the intercept of the regression line

Step-by-step explanation:

Multicollinearity is a term used in multiple regression analysis to show a high correlation between independent variables of a study.

Since it deals with independent variables correlation, it means it must be found before getting the regression equation.

Now, looking at the options, the one that doesn't relate with multicollinearity is option A because the intercept of the regression line is the value of y that is predicted when x is 0. Meanwhile, multicollinearity from definition above does in no way change the intercept of the regression line because it doesn't predict the y-value when x is zero.

7 0
3 years ago
Simplify this please​
Ugo [173]

Answer:

\frac{12q^{\frac{7}{3}}}{p^{3}}

Step-by-step explanation:

Here are some rules you need to simplify this expression:

Distribute exponents: When you raise an exponent to another exponent, you multiply the exponents together. This includes exponents that are fractions. (a^{x})^{n} = a^{xn}

Negative exponent rule: When an exponent is negative, you can make it positive by making the base a fraction. When the number is apart of a bigger fraction, you can move it to the other side (top/bottom). a^{-x} = \frac{1}{a^{x}}, and to help with this question: \frac{a^{-x}b}{1} = \frac{b}{a^{x}}.

Multiplying exponents with same base: When exponential numbers have the same base, you can combine them by adding their exponents together. (a^{x})(a^{y}) = a^{x+y}

Dividing exponents with same base: When exponential numbers have the same base, you can combine them by subtracting the exponents. \frac{a^{x}}{a^{y}} = a^{x-y}

Fractional exponents as a radical: When a number has an exponent that is a fraction, the numerator can remain the exponent, and the denominator becomes the index (example, index here ∛ is 3). a^{\frac{m}{n}} = \sqrt[n]{a^{m}} = (\sqrt[n]{a})^{m}

\frac{(8p^{-6} q^{3})^{2/3}}{(27p^{3}q)^{-1/3}}        Distribute exponent

=\frac{8^{(2/3)}p^{(-6*2/3)}q^{(3*2/3)}}{27^{(-1/3)}p^{(3*-1/3)}q^{(-1/3)}}        Simplify each exponent by multiplying

=\frac{8^{(2/3)}p^{(-4)}q^{(2)}}{27^{(-1/3)}p^{(-1)}q^{(-1/3)}}        Negative exponent rule

=\frac{8^{(2/3)}q^{(2)}27^{(1/3)}p^{(1)}q^{(1/3)}}{p^{(4)}}        Combine the like terms in the numerator with the base "q"

=\frac{8^{(2/3)}27^{(1/3)}p^{(1)}q^{(2)}q^{(1/3)}}{p^{(4)}}        Rearranged for you to see the like terms

=\frac{8^{(2/3)}27^{(1/3)}p^{(1)}q^{(2)+(1/3)}}{p^{(4)}}        Multiplying exponents with same base

=\frac{8^{(2/3)}27^{(1/3)}p^{(1)}q^{(7/3)}}{p^{(4)}}        2 + 1/3 = 7/3

=\frac{\sqrt[3]{8^{2}}\sqrt[3]{27}p\sqrt[3]{q^{7}}}{p^{4}}        Fractional exponents as radical form

=\frac{(\sqrt[3]{64})(3)(p)(q^{\frac{7}{3}})}{p^{4}}        Simplified cubes. Wrote brackets to lessen confusion. Notice the radical of a variable can't be simplified.

=\frac{(4)(3)(p)(q^{\frac{7}{3}})}{p^{4}}        Multiply 4 and 3

=\frac{12pq^{\frac{7}{3}}}{p^{4}}        Dividing exponents with same base

=12p^{(1-4)}q^{\frac{7}{3}}        Subtract the exponent of 'p'

=12p^{(-3)}q^{\frac{7}{3}}        Negative exponent rule

=\frac{12q^{\frac{7}{3}}}{p^{3}}        Final answer

Here is a version in pen if the steps are hard to see.

5 0
3 years ago
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