Answer:
Amount of Winter sealer for 2 coats[in square feet] = 576 square feet
Step-by-step explanation:
Given:
Length of drive way at garage door = 12 feet
Length of drive way at street = 20 feet
Length of total driveway = 18 feet
Find:
Amount of Winter sealer for 2 coats[in square feet]
Computation:
Amount of Winter sealer for 2 coats[in square feet] = 2[Area of trapezoid]
Amount of Winter sealer for 2 coats[in square feet] = 2[(1/2)(Sum of parallel side)(Height)]
Amount of Winter sealer for 2 coats[in square feet] = 2[(1/2)(12 + 20)(18)]
Amount of Winter sealer for 2 coats[in square feet] = 2[(1/2)(32)(18)]
Amount of Winter sealer for 2 coats[in square feet] = 32 x 18
Amount of Winter sealer for 2 coats[in square feet] = 576 square feet
32, 38, so on. So its +4 then +8 then +12 +16 +20....
Answer:
-12 3/5
Step-by-step explanation:
-4 3/10 - 8 3/10
The signs are the same so we add and then take the sign
4 3/10 + 8 3/10
Add the whole numbers
4+8 = 12
Add the fractions
3/10 + 3/10 = 6/10
Simplify the fraction
6/10 = 3/5
Put them together
12 3/5
Add the sign
-12 3/5
Answer: B (the lower one)
Step-by-step explanation:
First let's solve for y.
x + 2y = 4
2y = -x + 4
y = -1/2x + 2
It is B since the y intercept for that graph is 2.
Answer:
Formula for nth term in Arithmetic sequences is:
where a is the first term, d is the common difference and n is the number of terms.
As per the statement:
The rule for the pattern is add 4.
As the first term in line says the first term i,e 7
common difference(d)= 7
As the Jenna number is 8th in line.
Series we get;
7, 11, .........
We have to find the 8th term.
n = 8, a = 7 and d = 4
Using above formula:
Therefore, 35 number should Jenna say.
