What is the length of AC ?

What is the equation of the line in the graph below?

Furkat [3]

Answer:

y=1x+-3

Step-by-step explanation:

using rise over run we can see that we go up one from a point and over 1 from a point making our slope 1. then you you find the y-intercept and here that is very easy because we can clearly see the line pass through -3 on the y axis. the just substitute in your values to get y=1x+-3

3 0

3 years ago

Determine, without graphing, whether the graphs of the given equations are parallel, perpendicular, or neither. Explain your r

Inessa05 [86]

The graphs of the given equations are parallel.

<h3>What is the slope-intercept form of a line?</h3>

The slope-intercept form of a line is y = mx +c where m is the slope of the line and c is the y-intercept.

The given equations are y = x +10 and y = x+5.

The equations are in the slope-intercept form of y = mx +b.

Therefore, the slopes of both lines are 1.

Two lines are parallel if they have the same slope.

Therefore, the graphs of the given equations are parallel.

To learn more about the slope-intercept form of a line, click here:

brainly.com/question/9682526

#SPJ1

8 0

1 year ago

Can someone answer this question please please help me I really need it if it’s correct I will mark you brainliest .

Harman [31]

Formula for the perimeter of a quarter circle: C = ((pi x 2r) / 4) + 2r

C = ((3.14 x 18) / 4) + 18

C = (56.52 / 4) + 18

C = 14.13 + 18

C = 32.13 miles

Hope this helps! :)

5 0

4 years ago

How do I find ac in this problem

suter [353]

7 / x+4 = 5/x+1 =

5x+20 = 7x+7 =

20=2x+7

13=2x

x=13/2 = 6.5

6.5+4 = 10.5

6.5+1 =7.5

10.5+7.5 = 18

length of AC = 18

8 0

3 years ago

The weights of a certain dog breed are approximately normally distributed with a mean of 49 pounds, and a standard deviation of

AlekseyPX

Answer:

a. 74.86%

b. 50%

c. 50%

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with a mean of 49 pounds, and a standard deviation of 6 pounds.

This means that $\mu = 49, \sigma = 6$

a. Find the percentage of dogs of this breed that weigh less than 53 pounds.

The proportion is the p-value of Z when X = 53. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{53 - 49}{6}$

$Z = 0.67$

$Z = 0.67$ has a p-value of 0.7486.

0.7486*100% = 74.86%, which is percentage of dogs of this breed that weigh less than 53 pounds.

b. Find the percentage of dogs of this breed that weigh less than 49 pounds.

p-value of Z when X = 49, so:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{49 - 49}{6}$

$Z = 0$

$Z = 0$ has a p-value of 0.5

0.5 = 50% of dogs of this breed that weigh less than 49 pounds.

c. Find the percentage of dogs of this breed that weigh more than 49 pounds.

1 subtracted by the p-value of Z when X = 49, so:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{49 - 49}{6}$

$Z = 0$

$Z = 0$ has a p-value of 0.5.

1 - 0.5 = 0.5 = 50% of dogs of this breed that weigh more than 49 pounds.

8 0

3 years ago