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3 years ago

PLZZZ HELP ME WITH THESE 4 QUESTIONS THX SO MUCH!! ( 80 POINTSSSSS!!!!)

Mathematics

1 answer:

katrin2010 [14]3 years ago

7 0

For section 3.01 black, number 1 is correct, but number 2 is wrong.

When you raise an exponent to an exponent, you multiply the 2 exponents.

(x^4)^5 is x^20.

Number 3 is also right.

For 3.02, you use the interest formula. (1 + i/100)^t times x

x is the amount of money you have originally. i is the interest rate, t is the time.

1,500(1.03)^5 = 1738.91111145

$1738.91

For section 3.01 red in fractional exponents the numerator are the powers and the denominator is the root.

$\sqrt[4]{a^{3} } = a^{\frac{3}{4} }$

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(-11x^2 +6) - (14x^2 +2)

Nataly [62]

Answer:

−1(5−2)(5+2)

Step-by-step explanation:

Eliminate redundant parentheses

(−11²+6)−1(14² +2)

Distribute

−11² + 6 -- 1(14² +2)

−11² + 6 - 14² − 2

8 0

2 years ago

Find the speed ..

r-ruslan [8.4K]

38
430
49
mph I think... maybe

6 0

3 years ago

Patrick has just finished building a pen for his new dog. The pen is 3 feet wider than it is long. He also built a doghouse to p

zalisa [80]

General Idea:

(i) Assign variable for the unknown that we need to find

(ii) Sketch a diagram to help us visualize the problem

(iii) Write the mathematical equation representing the description given.

(iv) Solve the equation by substitution method. Solving means finding the values of the variables which will make both the equation TRUE

Applying the concept:

Given: x represents the length of the pen and y represents the area of the doghouse

Statement 1: "The pen is 3 feet wider than it is long"

$Length \; of\; the \; pen = x\\ Width \; of\; the\; pen=x+3$

------

Statement 2: "He also built a doghouse to put in the pen which has a perimeter that is equal to the area of its base"

$Area \; of\; the\; Dog \; house=y\\ Perimeter \; of\; Dog\; house=y$

------

Statement 3: "After putting the doghouse in the pen, he calculates that the dog will have 178 square feet of space to run around inside the pen."

$Area \; of \; the\; Pen - Area \;of \;the\;Dog \;House=\;Space\;inside\;Pen\\ \\ x \cdot (x+3)-y=178\\ Distributing \;x\;in\;the\;left\;side\;of\;the\;equation\\ \\ x^2+3x-y=178\Rightarrow\; 1^{st}\; Equation\\$

------

Statement 4: "The perimeter of the pen is 3 times greater than the perimeter of the doghouse."

$Perimeter\; of\; the\; Pen=3\; \cdot \; Perimeter\; of\; the\; Dog\; House\\ \\ 2(x \; + \; x+3)=3 \cdot y\\ Combine\; like\; terms\; inside\; the\; parenthesis\\ \\ 2(2x+3)=3y\\ Distribute\; 2\; in\; the\; left\; side\; of\; the\; equation\\ \\ 4x+6=3y\\ Subtract \; 6\; and \; 3y\; on\; both\; sides\; of\; the\; equation\\ \\ 4x+6-3y-6=3y-3y-6\\ Combine\; like\; terms\\ \\ 4x-3y=-6 \Rightarrow \; \; 2^{nd}\; Equation\\$

Conclusion:

The systems of equations that can be used to determine the length and width of the pen and the area of the doghouse is given in Option B.

$178=x^2+3x-y\\ \\ -6=4x-3y$

8 0

3 years ago

Read 2 more answers

Select all the correct answers. Which statements are true about function g? NO LINKS!!!

Anna35 [415]

Answer:

A, B, E

Step-by-step explanation:

The attachment shows a graph of the function. It tends to infinity for x going to infinity in either direction. (A, B are true)

The right-side piece is cubic, not quadratic.

The U-shape tells you the function is decreasing on the left side.

The two function definitions have the same value at x=2, so the function has no discontinuities. It is continuous. (E is true)

3 0

2 years ago

4 divided by 2/9? If you could, please also explain.

shtirl [24]

You do 4/1 divided by 2/9

4 2
_ divided by _

1 9

Equals 18

(You have to multiply by the reciprocal)

4/1 times 1/4
And
2/9 times 1/4

Hope I helped!!!

7 0

3 years ago